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Bingel [31]
3 years ago
7

Help plzzz!! Marking most Brainly;)

Mathematics
1 answer:
kolezko [41]3 years ago
3 0

Answer:

D it

Step-by-step explanation:

We have two equations, A quadratic and a linear equation.

The domain of a linear equation and quadratic equation is all real numbers but since it dealing with time we must make sure the roots or x-intercepts is positive.

Looking at the quadratic equation, we can use the discramnt formula to see if all roots are positve.

b {}^{2} - 4ac

{ - 6}^{2}  - 4(1)(8.75)

36 - 35 = 1

The discramnt is greater than zero so there is two distinct real roots. So let check if they are positve

If you graph the equation, it intercepts at two positve roots so it is D

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<img src="https://tex.z-dn.net/?f=%20-%2010%20%5Ctimes%2018%20%7Br%7D%5E%7B%20-%208%7D%20%20%3D%20%20-%202" id="TexFormula1" tit
grigory [225]

Answer:

1.107   =  r

Step-by-step explanation:

To solve this for r, do the following:

Add 10 to both sides, to isolate the r term on the left:  18r^(-8) = 8

Divide both sides by 18, to isolate r^(-8):   r^(-8) = 8/18

Invert both sides:  r^8 = 9/4

Take the natural log or both sides:

8 ln r = ln 9 - ln 4, or

8 ln r = 0.8109, so that ln r = 0.1014

to find r, raise e to the power ln r on the left and e to the power 0.1014 on the right:

  ln r           0.1014

e         =    e              =  1.107   =  r

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