Perimiter=6 times legnth of one side
P=6(x+1/3y)
P=6x+6/3y
P=6x+2y
if x=5 and y=6
P=6(5)+2(6)
P=30+12
P=42
A. P=6x+2y
B. 42 units is the perimiter
Answer:
n=37
Step-by-step explanation:
45-8=37
In math, "of" almost always means "times".
So your question is: 3/7 times (the number) = 9
Multiply each side of that equation by 7 : 3 times (the number) = 63
Divide each side by 3 : <em> The number = 21</em>
Ok so to find which sides are congruent we need to know their lengths.
To find the length we need the distance formula between two point ->
√(X2-X1)∧2 +(Y2-Y1)∧2
Ok lets find the first side PQ
P(-1,3) Q(2,-1)
X1 Y1 X2 Y2
√(2-(-1)∧2 + (-1-3)∧2 = 5
Now PR
P (-1,3) R (5,3)
X1 Y1 X2 Y2
√(5-(-1))∧2 + (3-3)∧2) = 6
Now the last side QR
Q (2, -1) R (5,3)
X1 Y1 X2 Y2
√(5-2)∧2 + (3-(-1))∧2 = 5
From the above work we see that PQ and QR are congruent becuase they are equal PQ=QR
Also the opposite angles of these sides are congruent. Hope this helps :).