Answer:
Cubic polynomial has zeros at x=−1x=−1 and 22, is tangent to x−x−axis at x=−1x=−1, and passes through the point (0,−6)(0,−6).
So cubic polynomial has double zero at x=−1x=−1, and single zero at x=2x=2
f(x)=a(x+1)2(x−2)f(x)=a(x+1)2(x−2)
f(0)=−6f(0)=−6
a(1)(−2)=−6a(1)(−2)=−6
a=3a=3
f(x)=3(x+1)2(x−2)f(x)=3(x+1)2(x−2)
f(x)=3x3−9x−6
Answer:2nd one
Step-by-step explanation:
Answer:
1.
Blank 1: y
Blank 2: x
2.
Blank 1: x
Blank 2: y
Step-by-step explanation:
The reflection of a point along y-axis means the <u>y</u><u> </u><u>value</u><u> </u><u> </u>stays the same and the <u>x-value</u><u> </u>changes its sign.
Blank 1: y
Blank 2: x
The reflection of a point along x-axis means the <u>x</u> value stays the same and the <u>y</u>-value changes its sign.
Blank 1: x
Blank 2: y
Answer:
Step-by-step explanation:
1. Cos 52° = adj/hyp
Cos 52° = x/13
x = 13×cos 52°
x = 8.00
2. Sin70° = opp/hyp
Sin70° = 30/x
x sin70° = 30
x = 30/sin70°
x = 31.93
x ≈ 32
3. Tan∅ = opp/adj
Tan∅ = 45/51
Tan∅ = 0.8824
∅ = tan-¹(0.8824)
∅ = 41.42°
∅ ≈ 41°
Answer:
72
Step-by-step explanation:
The area (A) of a rhombus is calculated as
A = 
× d₁ × d₂ (d₁ and d₂ are the diagonals )
The diagonals bisect each other at right angles
d₁ = 2 × 6 = 12
Use the tangent ration in the upper left right triangle and the exact value
tan60° =
tan60° = 
= 
= ( multiply both sides by 6 )
opp = 6 , then
d₂ = 2 × 6 = 12
Thus
A = × 12 × 12 = 6 × 12 = 72
