Point A is the midpoint of CT which means the ratio of CA:CT would be 1:2.
To find CT, you need to find the distance of CA then applies 2 times of the distance to the point C
Xca= Xa-Xc= 1- (-2)= 3
Yca= Ya- Yc= -3 -5= -8
Xt= Xc + 2* Xca= -2 + 2*3= 4
Yt= Yc + 2* Yca= 5 + 2*-8= -11
T(Xt, Yt)= T(4, -11)
The coordinate for point T would be (4, -11)
(-6y-2)+5(3+2.5y) expend
-6y-2+15+12.5
6.5y+13
In finding this value you average lower and upper bound
(0.6+0.82)/2 = 0.71
=0.71 estimated
margin of error = distance from estimate point lower/ upper bound
This interval will be twice margin error
(0.82-0.6)/2 = 0.11
How far is 0.82 from 0.71 ??
=0.11=11%
Answer:
16.83
Step-by-step explanation:
7.36
+ 9.47
----------
16.83
Answer:
Infinite number of solutions
Step-by-step explanation:
when you solve for V, you notice that the term in "v" goes away, and you end up with a true statement:
2 = 2
This is a true statement no matter what values the variable V has, so it is true for all possible (infinite) values of "v".
