Answer:
a. 0.48
b. 0.14
c. 0.47
Step-by-step explanation:
Data provided in the question
0 - 2 0.48
3 - 5 0.26
6 - 8 0.12
9- 11 0.09
12- 14 0.05
Based on the above information
a. The probability for fewer than three phobias is
= P( x < 3)
= 0.48
b. The probability for more than eight phobias is
= P( x >8)
= 0.09 + 0.05
= 0.14
c. Probability between 3 and 11 phobias is
= P(3 < x < 11)
= 0.26 + 0.12 + 0.09
= 0.47
Answer:
0.00665
0.006951
Step-by-step explanation:
If the first child is born with the affliction, there's a 0.05 probability that the second child will be born with the affliction. Which means there's a 0.95 probability that they won't.
The probability that the first child is born with the affliction but not the second is therefore:
P = 0.007 × 0.95
P = 0.00665
There's a 0.007 probability that the first child will be born with the affliction, which means there's a 0.993 probability that they won't. If the first child isn't born with the affliction, then the probability the second child will have it is 0.007.
So the probability that the first child is not born with the affliction and the second child is would be:
P = 0.993 × 0.007
P = 0.006951
Answer:
Inequality Form:
h
>
6
Interval Notation:
(
6
,
∞
)
Step-by-step explanation:
Isolate the variable by dividing each side by factors that don't contain the variable.
Answer:
84 degrees
Step-by-step explanation:
The two angles are supplementary (their sum is 180 degrees)
96 + b = 180
b = 180 - 96
b = 84
