Answer with Explanation:
We are given that
Angle of incidence,
Angle of refraction,
a.Refractive index of air,
We know that
b.Wavelength of red light in vacuum,
Wavelength in the solution,
c.Frequency does not change .It remains same in vacuum and solution.
Frequency,
Where
Frequency,
d.Speed in the solution,
Answer:
See answers below
Explanation:
vf = vi + gt
0 = (120sin55°) + (-9.8)t
t = 12.2 s
12.2 x 2 = 24.4 s
x = (vi)t + (1/2)at²
x = (120cos55°)(24.4) + 0
x = 64.79 m
a.
vf = vi + gt
0 = (120sin55°) + (-1.6)t
t = 74.98 s
74.98 x 2 = 149.96 s
x = (vi)t + (1/2)at²
x = (120cos55°)(149.96) + 0
x = 398.18 m
(a) frequency of the wave
The electromagnetic wave travels at the speed of light:
. Since its wavelength is
, we can find the frequency of the wave by using the relationship between f,
and c:
(b) magnetic field amplitude
The relationship between the electric field amplitude E, the magnetic field amplitude B and the speed of light c for an electromagnetic wave is
And since we know E, by re-arranging the equation we can find the magnitude of B: