Answer:
m = 0.164 kg
Explanation:
T (period)
k (force/spring constant)
m (mass)
T = 2*Pi*sqrt(m/k)
T/(2*Pi) = sqrt(m)/sqrt(k)
(T/(2*Pi))*sqrt(k) = sqrt(m)
m = ((T/(2*Pi))*sqrt(k))^2
m = 4.5*((1.2/(2*Pi)))^2
m = 0.1641403175
D. I know that like the back of my hand
Answer:
F=1.65 x 10²⁶ N
Explanation:
Given that
Distance ,R= 3.34 x 10¹² m
Mass m₁= 2.78 x 10³⁰ kg
Mass ,m₂= 9.94 x 10³⁰ kg
we know that gravitational force F given as

G=Constant
G=6.67 x 10⁻¹¹ Nm²/kg²
Now by putting the values

F=1.65 x 10²⁶ N
Therefore the force between these two mass will be 1.65 x 10²⁶ N.
Answer:
a) 1.06*10^-5
b) 0.00105 °C^-1
Explanation:
Given that
Length of the cylinder, L = 1.5 m
Radius of the cylinder, r = 0.25 cm
Voltage across the rod, V = 15 V
I• at Temperature T• = 20° C is 18.5 A
I at Temperature T = 90° C is 17.2 A
See attachment for calculations