3 years ago

1) acute AOB2) acute BOC 3) Obtuse COD4) acute AOD

Mathematics

1 answer:

hoa [83]3 years ago

4 0

66. Tip: subtract all known angles from 360 to find unknown angle

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Give the common denominator (LCD) OF

RideAnS [48]

What’s the number then I could help

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3 years ago

Olives garden is only 10 yd.² and the watermelon plants she wants to grow require 2.5 yd squared each how many watermelon plants

Ad libitum [116K]

Answer:

The answer is<em> 4.</em>

Step-by-step explanation:

Olives garden has area= $10 yd^2$

Each watermelon plants she want to grow require an area= $2.5 yd^2$

Hence, the number of watermelon plants she can grow in that garden is given by:

Number of watermelon plants she can grow= (Total area)/( Area 1 watermelon plant requires)

Hence, Number of watermelon plants she can grow= $\dfrac{10}{2.5}=4$

Hence, she can grow 4 watermelon plants in Olives garden.

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3 years ago

Dan rides his bike to town every eighth day. Sue walks to town every third day. On what day are they likely to meet in town

mr Goodwill [35]

They are most likely to meet on the 24th since it is a common multiple of both 8 and 3.

4 0

3 years ago

How do you find the solution of this proportion?<br> 4/9 = m2-1/54 <br> m2 is m to the power of 2

elena-14-01-66 [18.8K]

Answer:

±5sqrt(6)/6 = m

Step-by-step explanation:

4/9 = m^2-1/54

Add 1/54 to both sides

4/9+ 1/54 = m^2-1/54 +1/54

4/9+ 1/54 = m^2

Get a common denominator of 54

4/9 *6/6 + 1/54 = m^2

24/54 + 1/54 = m^2

25/54 = m^2

Take the square root of each side

±sqrt(25/54) = sqrt(m^2)

±sqrt(25/54) = m

±sqrt(25)/sqrt(54) = m

±sqrt(25)/sqrt(9)sqrt(6) = m

±5/3sqrt(6) = m

±5/3sqrt(6) *sqrt(6)/sqrt(6) = m

±5sqrt(6)/3*6 = m

±5sqrt(6)/6 = m

8 0

3 years ago

Find x when y=14, if y=7 when X=8

TEA [102]

When y= 14, if y= 7 then x= 16 if x= 8. you just double your number

8 0

3 years ago

1) acute AOB2) acute BOC 3) Obtuse COD4) acute AOD​

1) acute AOB2) acute BOC 3) Obtuse COD4) acute AOD