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Mathematics

2 answers:

murzikaleks [220]4 years ago

6 0

Oh hello again, if you are rounding, then it would be 123/500.

valentinak56 [21]4 years ago

5 0

246/1000 or 123/500 hope this helps

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Consider that point A is reflected across the y-axis. What is the distance between point A and the point of its reflection?

Arisa [49]

Answer:

Step-by-step explanation:

Under a reflection in the y- axis

a point (x, y ) → (- x, y ), thus

A(3, 4 ) → A'(- 3, 4 )

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distance between = | 3 + 3 | = | 6 | = 6

7 0

3 years ago

Find the following:

Butoxors [25]

Answer:

Step-by-step explanation:

Limit refers to the value that the function approaches as the input approaches some value.

We say $\displaystyle \lim_{x\rightarrow a}f(x)=L$ , if f(x) approaches L as x approaches 'a'.

(a)

$\displaystyle \lim_{x\rightarrow 5}\left ( \frac{f(x)-8}{x-5} \right )=4\\\frac{\displaystyle \lim_{x\rightarrow 5}f(x)-\displaystyle \lim_{x\rightarrow 5}8}{\displaystyle \lim_{x\rightarrow 5}x-\displaystyle \lim_{x\rightarrow 5}5}=4\\$

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$\displaystyle \lim_{x\rightarrow 5}f(x)-8=20-20=0\\\displaystyle \lim_{x\rightarrow 5}f(x)=8$

(b)

$\displaystyle \lim_{x\rightarrow 5}\left ( \frac{f(x)-8}{x-5} \right )=7\\\frac{\displaystyle \lim_{x\rightarrow 5}f(x)-\displaystyle \lim_{x\rightarrow 5}8}{\displaystyle \lim_{x\rightarrow 5}x-\displaystyle \lim_{x\rightarrow 5}5}=7\\\frac{\displaystyle \lim_{x\rightarrow 5}f(x)-8}{\displaystyle \lim_{x\rightarrow 5}x-5}=7\\$

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