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-BARSIC- [3]
3 years ago
7

Solve the simultaneous equations.

Mathematics
1 answer:
user100 [1]3 years ago
6 0

Answer:

x=3/2, y=-1/2

Step-by-step explanation:

2x+4y =1

3x-5y =7

We will use elimination to solve these

Multiply the first equation by 3

3(2x+4y =1)       6x +12y =3

Multiply the second equation by -2  so that the x coefficients are the opposites of each other (6 and -6)

-2(3x-5y =7)     -6x +10y =-14

Add the two new equations together

6x +12y =3

-6x +10y =-14

--------------------

0   + 22y = -11

Divide each side by 22

22y/22 = -11/22

y = -1/2

Now we can substitute y=-1/2 into the first equation and solve for x

2x + 4y =1

2x +4(-1/2) =1

2x -2 =1

Add 2 to each side

2x-2+2=1+2

2x=3

Divide by 2

2x/2 =3/2

x = 3/2

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7 0
3 years ago
Which graph represents the following piecewise defined function?
kenny6666 [7]
The correct answer is shown in attached figure
To find the correct graph, we should study the continuity of the function

Check the continuity at x = -2
from the left ⇒⇒ f(-2) = 1/2 * -2 + 3 = 2
from the right ⇒⇒ f(-2) = 2
∴ The function is continuous at x = -2

Check the continuity at x = 3
from the left ⇒⇒ f(3) = 2
from the right ⇒⇒ f(3) = 2*3 - 3 = 3
∴ The function is jump discontinuous at x = 3


From the previous results the correct graph is the last as shown in attached graph.



5 0
3 years ago
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Step-by-step explanation:

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