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marishachu [46]
3 years ago
6

PLEASE!!!!!!

Mathematics
1 answer:
liubo4ka [24]3 years ago
3 0

Answer:

wait whaaaaaaaat? like turn it into an equation?

Step-by-step explanation:

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Which of these ordered pairs could you remove to make this relation a function? {(-2,1), (-1, -5), (-1,5), (0, -7), (2, 1)}
balandron [24]

Answer:

Either (-2,1) or (2,1)

Step-by-step explanation:


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Generate the first five terms in the sequence using explicit formula
ioda
I got b i did this question before but dont take my word for it im not one hundred percent sure

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Answer quick and i’ll mark branliest. Tomas makes balloon sculptures at a circus. In 96 minutes, he uses 160 balloons to make 32
MissTica

Answer:

3 min.

5 balloons.

Step-by-step explanation:

How many minutes does it take to make one balloon sculpture?

t = (Total time) /  (Total identical  balloon sculptures) = 96 / 32 = 3 min.

How many balloons are used in one  sculpture?

n = (Total balloons) /  (Total identical  balloon sculptures) = 160 / 32 = 5 balloons.

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The table and the graph below each show a different relationship between the same two variables, x and y: (picture below)
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4 0
4 years ago
Problem:
Molodets [167]

Answer:

a)

We know that:

a, b > 0

a < b

With this, we want to prove that a^2 < b^2

Well, we start with:

a < b

If we multiply both sides by a, we get:

a*a < b*a

a^2 < b*a

now let's go back to the initial inequality.

a < b

if we now multiply both sides by b, we get:

a*b < b*b

a*b < b^2

Then we have the two inequalities:

a^2 < b*a

a*b < b^2

a*b = b*a

Then we can rewrite this as:

a^2 < b*a < b^2

This means that:

a^2 < b^2

b) Now we know that a.b > 0, and a^2 < b^2

With this, we want to prove that a < b

So let's start with:

a^2 < b^2

only with this, we can know that a*b will be between these two numbers.

Then:

a^2 < a*b < b^2

Now just divide all the sides by a or b.

if we divide all of them by a, we get:

a^2/a < a*b/a < b^2/a

a < b < b^2/a

In the first part, we have a < b, this is what we wanted to get.

Another way can be:

a^2 < b^2

divide both sides by a^2

1 < b^2/a^2

Let's apply the square root in both sides:

√1 < √( b^2/a^2)

1 < b/a

Now we multiply both sides by a:

a < b

7 0
3 years ago
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