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nikklg [1K]
4 years ago
12

Gretchen lives in Florida, for the current temperature 69°F and rising at a rate of 2°F per hour. She's talking on the phone to

her friend in Indiana where the temperature is now 84°F and falling at a rate of 3°F per hour.
A.) If the temperature continue changing at the same rates, how many hours would Gretchen and her friend have to talk before the temperature become equal?
B.) What will the temperature be?
Mathematics
2 answers:
mixer [17]4 years ago
7 0
69 + 2h = 84 - 3h
2h + 3h = 84 - 69
5h = 15
h = 15/5
h = 3 <=== the temps will be the same in 3 hrs

69 + 2(3) = 69 + 6 = 75
84 - 3(3) = 84 - 9 = 75

and the temps will both be 75 F <==


AfilCa [17]4 years ago
3 0

Answer:

A) Gretchen and her friend have to talk 3 hours before the temperature become equal.

B) The temperature after 3 hours will be 75°F.

Step-by-step explanation:

Current temperature in Florida = 69°F

Rate at which temperature is rising = 2°F per hour

Current temperature in Indiana = 84°F

Rate at which temperature is falling= 3°F per hour

A) Suppose in x hours both places have same temperature:

69^oF +2F^o\times x=84^oF-3^oF\times x

5x=84^oF-69^oF

x = 3 hours

Gretchen and her friend have to talk 3 hours before the temperature become equal.

B) The temperature after 3 hours:

x  = 75°F

69^oF +2F^o\times x=69^oF +2F^o\times 3=75^oF

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3 years ago
Find the equation of the lines parallel and perpendicular to the line 5x+2y=12 through the point (-2,3)
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Answer:

The equation of line parallel to given line and passing through points        ( - 2 , 3 ) is 5 x + 2 y + 4 = 0

The equation of line perpendicular to given line and passing through points ( - 2 , 3 ) is 2 x - 5 y + 19 = 0

Step-by-step explanation:

Given equation of line as :

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y =  \frac{-5}{2} x - 2

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<u>Similarly</u>

The other line if passing through the points (- 2 , 3 ) And  is perpendicular  to given line

So, for perpendicular lines condition,the products of slope of both lines = - 1

Let The slope of other line = M'

So,  M' × m = - 1

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∴ The equation of line with slope M and passing through points ( -2 , 3) is

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So, 3 = \frac{2}{5} × ( - 2 ) + c'

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Or, 3 × 5 = - 4 + 5× c'

∴  5 c' = 15 + 4

or, 5 c' = 19

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Other options you could use are these identities

\cos(2\theta) = 2\cos^2(\theta)-1\\\\

or

\cos(2\theta) = 1-2\sin^2(\theta)\\\\

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