Not saying my answer is 100% correct but I quickly tried to solve this and got 72.
(2x36, 6x12, 8x9)
Answer:
x=8
Step-by-step explanation:
Is this the answer you wanted if not I can change it
The information given to us shows that triangles XYZ and JKL is not enough to prove they are congruent by AAS, ASA, nor SAS.
<h3>The Triangle Congruence Theorems</h3>
- Two triangles are congruent by the AAS congruence theorem if they both have two pairs of congruent angles and a pair of congruent non-included sides.
- Two triangles are congruent by the ASA congruence theorem if they both have two pairs of congruent angles and a pair of congruent included sides.
- Two triangles are congruent by the SAS congruence theorem if they both have two pairs of congruent sides and a pair of congruent included angles.
Thus, the information given to us shows that triangles XYZ and JKL is not enough to prove they are congruent by AAS, ASA, nor SAS.
Learn more about triangle congruence theorem on:
brainly.com/question/2579710
Answer:
x = 3
Step-by-step explanation:
Subtract 8x from both sides.
3x+4−8x=8x−11−8x
−5x+4=−11
Subtract 4 from both sides.
−5x+4−4=−11−4
−5x=−15
Divide both sides by -5.
−5x
−5
=
−15
−5
x=3
Answer:
1 / 7 (x - 2)
Step-by-step explanation:
x - 2 / 7(x - 2)^2
= (x - 2) / 7 (x - 2) (x - 2)
= 1 / 7 (x - 2)