Cross multiplication, 3(9+x) = 63
27+3x = 63
3x = 63-27 = 36
x=36/3=12
The rule for this one is called the difference of squares
A^2 - b ^2 = (a+b)(a-b)
Using this rule
N^2 - 62 = (n+ sqrt(62)) (n - sqrt(62))
The solution for this one is to make the statement = 0
0 = (n+ sqrt(62)) (n - sqrt(62))
N can either be +- sqrt(62)
21 could be wrong but 5 players get 4 wins each before the one players gets the last needed win
