The mean absolute deviation for 1,2,2,2,3,3,3,3,3,3,3,3,4,4,4,4,4,4,5
antoniya [11.8K]
Answer:
7/10
Step-by-step explanation:
To find the MAD or mean of absolute deviation, we first have to find the mean.
Part I. Finding the mean.
To find the mean we add all the numbers up and divide it by the total number of numbers.
So we get:
(1+2+2+2+3+3+3+3+3+3+3+3+4+4+4+4+4+4+4+5) as our sum. This adds up to a total of 60. Since we have a total of 20 numbers, we divide 60 by 20 and get 3. So now we need to find the MAD.
Part II. Finding the MAD.
To find the MAD, we take the absolute value of the mean minus the numbers and divide that by the number of numbers. So we get the MAD to be 14/20 or 7/10.
Answer:
24 is the answer
Step-by-step explanation:
answer is 24 for base
Answer:
the value of k is 6 and 12.
Step-by-step explanation:
The differential equation is y" – 18y' + 72y = 0.
A solution of this differential equation is
![y(x)=e^{kt}](https://tex.z-dn.net/?f=y%28x%29%3De%5E%7Bkt%7D)
The first derivative is
![y'(x)=ke^{kt}](https://tex.z-dn.net/?f=y%27%28x%29%3Dke%5E%7Bkt%7D)
The second derivative is
![y''(x)=k^2e^{kt}](https://tex.z-dn.net/?f=y%27%27%28x%29%3Dk%5E2e%5E%7Bkt%7D)
Substituting these values in the given DE
![k^2e^{kt}-18ke^{kt}+72e^{kt}=0](https://tex.z-dn.net/?f=k%5E2e%5E%7Bkt%7D-18ke%5E%7Bkt%7D%2B72e%5E%7Bkt%7D%3D0)
Factor out the GCF
![e^{kt}(-k^2-18k+72)=0](https://tex.z-dn.net/?f=e%5E%7Bkt%7D%28-k%5E2-18k%2B72%29%3D0)
The function
can never be zero. Hence, we have
![k^2-18k+72=0\\\\k^2-12k-6k+72=0\\\\k(k-12)-6(k-12)=0\\\\(k-12)(k-6)=0\\\\k=6,12](https://tex.z-dn.net/?f=k%5E2-18k%2B72%3D0%5C%5C%5C%5Ck%5E2-12k-6k%2B72%3D0%5C%5C%5C%5Ck%28k-12%29-6%28k-12%29%3D0%5C%5C%5C%5C%28k-12%29%28k-6%29%3D0%5C%5C%5C%5Ck%3D6%2C12)
Therefore, the value of k is 6 and 12.
Smaller value = 6
Larger value = 12
Thirty-six and six thousand two ten thousandths = 36.6002