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Ann [662]
3 years ago
8

Find the length of a line joining the point ( 4,3 ) and origin .​

Mathematics
2 answers:
vesna_86 [32]3 years ago
7 0

Answer:

d=5

Step-by-step explanation:

you have to use the distance formula, making the origin (0,0) the 1st point and (4,0) the second point.

d=\sqrt{(x_{2} -x_{1})^{2}  + (y_{2} -y_{1})^{2}   }

d=\sqrt{(4-0)^{2}+(3-0)^2 }

d=\sqrt{(4)^2+(3)^2}

d=\sqrt{16+9}

d=\sqrt{25}

d=5

GalinKa [24]3 years ago
5 0

Answer:

i think you have to count till you get to 4 or 3 then the remaining you plus with the 3

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Which is farthest 3.345, 3.35, or 3.3 meters
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3 years ago
Solve –4(6x + 3) = –12(x + 10). A. x = 2 B. x = 9 C. x = 5 D. x = –5
sergey [27]
–4(6x + 3) = -12<span>(x + 10)
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answer
</span><span>B. x = 9</span><span>

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6 0
3 years ago
<img src="https://tex.z-dn.net/?f=2x%5E2%2B5x%2B3%3D0" id="TexFormula1" title="2x^2+5x+3=0" alt="2x^2+5x+3=0" align="absmiddle"
melamori03 [73]

Answer:

x=-\frac{3}{2},-1

Step-by-step explanation:

2x^2+5x+3=0

Split the second term (5x) into two terms. Multiply the coefficient of the first term (2) by the constant term (3):

2*3=6

Find which two numbers add up to 5 and multiply into 6:

3+2=5\\3*2=6\\3,2

Split 5x as the sum of 3x and 2x:

2x^2+3x+2x+3

Now factor out a common term for the first 2 terms:

2x^2+3x\\x(2x+3)

And do the same for the last 2 terms:

2x+3\\1(2x+3)

Re-insert:

x(2x+3)+1(2x+3)=0

Factor out the common term 2x+3 and insert the values in front of the parentheses (x and 1):

(2x+3)(x+1)=0

Separate the parentheses and equal them to 0. Solve for x:

2x+3=0\\2x+3-3=0-3\\2x=-3\\\\\frac{2x}{2}=\frac{-3}{2}\\\\  x=-\frac{3}{2}

and

x+1=0\\x+1-1=0-1\\x=-1

5 0
3 years ago
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