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3 years ago

I NEED HELP ASAP THANKSSS factor x^2 +9x+20

Mathematics

2 answers:

matrenka [14]3 years ago

6 0

Answer:

(x + 5)(x + 4)

Step-by-step explanation:

$x^{2} +9x+20=(x+5)(x+4)$

Reika [66]3 years ago

6 0

Answer:

Step-by-step explanation:

x^2+9x+20

(x+4)(x+5)

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Question 1

Alexxx [7]

Answer:

Water needed for pool = 486 cubic feet

Plastic liner required for the pool = 298.3 feet

Step-by-step explanation:

Top view of the pool is a composite figure, having one rectangle and a trapezoid.

1). Water needed for the pool = volume of the pool

Volume of the pool = Area of the base × Depth

= (Area of the rectangle + Area of the trapezoid)× depth

Area of the trapezoid = $\frac{1}{2}(b_{1}+b_{2})\times h$

= $\frac{1}{2}(11+9)\times (12-1.5)$

= 105 ft²

Area of the rectangle = Length × width

= 11 × 1.5

= 16.5 ft²

Now, volume of the pool = (105 + 16.5) × 4

= 121.5 × 4

= 486 cubic feet

b). Liner required = surface area of the pool excluding top

= Surface area of the walls + Area of the pool base

= (Perimeter of the pool) × depth + area of the base

= (12 + 11 + 1.5 + 10.7 + 9)×4 + 121.5

= 176.8 + 121.5

= 298.3 square feet

Therefore, amount of water required = 486 cubic feet

liner needed = 298.3 square feet

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2 years ago

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2 years ago

Ninety-one percent of products come off the line within product specifications. Your quality control department selects 15 produ

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Answer:

Probability of stopping the machine when $X < 9$ is 0.0002

Probability of stopping the machine when $X < 10$ is 0.0013

Probability of stopping the machine when $X < 11$ is 0.0082

Probability of stopping the machine when $X < 12$ is 0.0399

Step-by-step explanation:

There is a random binomial variable $X$ that represents the number of units come off the line within product specifications in a review of $n$ Bernoulli-type trials with probability of success $0.91$ . Therefore, the model is ${15 \choose x} (0.91) ^ {x} (0.09) ^ {(15-x)}$ . So:

$P (X < 9) = 1 - P (X \geq 9) = 1 - [{15 \choose 9} (0.91)^{9}(0.09)^{6}+...+{ 15 \choose 15}(0.91)^{15}(0.09)^{0}] = 0.0002$

$P (X < 10) = 1 - P (X \geq 10) = 1 - [{15 \choose 10}(0.91)^{10}(0.09)^{5}+...+{15 \choose 15} (0.91)^{15}(0.09)^{0}] = 0.0013$

$P (X < 11) = 1 - P (X \geq 11) = 1 - [{15 \choose 11}(0.91)^{11}(0.09)^{4}+...+{15 \choose 15} (0.91)^{15}(0.09)^{0}] = 0.0082$

$P (X < 12) = 1- P (X \geq 12) = 1 - [{15 \choose 12}(0.91)^{12}(0.09)^{3}+...+{15 \choose 15} (0.91)^{15}(0.09)^{0}] = 0.0399$

Probability of stopping the machine when $X < 9$ is 0.0002

Probability of stopping the machine when $X < 10$ is 0.0013

Probability of stopping the machine when $X < 11$ is 0.0082

Probability of stopping the machine when $X < 12$ is 0.0399

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3 years ago