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Vesnalui [34]
3 years ago
12

I NEED HELP ASAP THANKSSS factor x^2 +9x+20

Mathematics
2 answers:
matrenka [14]3 years ago
6 0

Answer:

(x + 5)(x + 4)

Step-by-step explanation:

x^{2} +9x+20=(x+5)(x+4)

Reika [66]3 years ago
6 0

Answer:

Step-by-step explanation:

x^2+9x+20

(x+4)(x+5)

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b) How many ways can you deal cards (from a deck of 52) to 4 people when each player gets 7 cards. 2 hidden and 5 visible. Assum
Mariana [72]

Answer:

{52 \choose 7}{45 \choose 7}{38 \choose 7}{31 \choose 7}{7 \choose 2}^4

Step-by-step explanation:

The dealing of the cards can be seen in the following way:

We first have to choose which 7 cards are going to be dealt to the 1st player. So we have to pick 7 cards out of the 52 available cards. This can be done in {52 \choose 7} ways. Now that we have chosen which 7 cards are going to be dealt to the 1st player, we have to choose which 2 of them are going to be the hidden ones. So we have to pick 2 cards out of the 7 cards to be the hidden ones. This can be done in {7 \choose 2} ways. At this point we now know which cards are being dealt to the 1st player, and which ones are hidden for him. Then we have to choose which 7 cards to deal to the 2nd player, out of the remaining ones. So we have to pick 7 out of 52-7=45. (since 7 have been already dealt to the 1st player). This can be done in {45 \choose 7}. Then again, we have to pick which 2 are going to be the hidden cards for this 2nd player. So we have to pick 2 out of the 7. This can be done in {7 \choose 2} ways. Then we continue with the 3rd player. We have to choose 7 cards out of the remaining ones, which at this point are 52-7-7=38. This can be done in {38 \choose 7}. And again, we have to choose which ones are the hidden ones, which can be chosen in {7 \choose 2} ways. Finally, for the last player, we choose 7 out of the remaining cards, which are 52-7-7-7=31. This can be done in {31 \choose 7} ways. And choosing which ones are the hidden ones for this player can be done in {7 \choose 2} ways. At the end, we should multiply all our available choices on each step, to get the total choices or total ways to deal the cards to our 4 players (since dealing the cards is a process of several steps with many choices on each step).

{52 \choose 7}{7 \choose 2}{45 \choose 7}{7 \choose 2}{38 \choose 7}{7 \choose 2}{31 \choose 7}{7 \choose 2}={52 \choose 7}{45 \choose 7}{38 \choose 7}{31 \choose 7}{7 \choose 2}^4

7 0
4 years ago
Why is 2 : 7 and 10,000 : 35,000
snow_tiger [21]

let's say 10000 ÷ 5000 = 2

35000 ÷ 5000 = 7

4 0
3 years ago
Read 2 more answers
What is it a ,b,c,or D can I get a step by step explanation
ANEK [815]
The answers are b and c. Plug in -4 for x and solve each option

2(-4) -8 = 0. 0 does not equal 1
3(-4) +8 = -4
1/2 * -4 + 3 = 1, -4+5 = 1
2(1- -4) = 10, -4 + 2 = -2
4 0
4 years ago
NEED BY MIDNIGHT JAN 11 2019
meriva
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3 0
3 years ago
2x + y = 4<br> y = 32 – 1<br> Is (1, 2) a solution to both equations?
Digiron [165]

Answer:

No

Step-by-step explanation:

y = 32 – 1 is  not true to (1,2) because y=2 and 2 does not equal 31.

6 0
3 years ago
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