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Alex17521 [72]
2 years ago
13

Hurry ASAP need help nowww

Mathematics
2 answers:
valina [46]2 years ago
8 0

Answer:

cant help sry

Step-by-step explanation:

irga5000 [103]2 years ago
5 0

Answer:

35

Step-by-step explanation:

80-45=35

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The quantity demanded x of a certain brand of DVD player is 3000/week when the unit price p is $485. For each decrease in unit p
ANTONII [103]

Answer:

Demand Equation: q = 15125 - 25p.

Supply Equation: 80p - 24000 = 9q.

Equilibrium Price: $525.

Equilibrium Quantity: 2000 units.

Step-by-step explanation:

To solve this question, first, the demand equation has to be calculated. Let price be on the y-axis and quantity by on the x-axis. It is given that p = $485 when q = 3000 units. This can also be written as (q₁, p₁) = (3000, 485). It is also given that when the price goes down by $20, the quantity increases by 500 units. Therefore, (q₂, p₂) = (3500, 465). Due to the statement "For each decrease in unit price of $20 below $485, the quantity demanded increases by 500 units", the demand function will be linear i.e. a straight line. This is because the word "for each" has been used. Therefore, finding the equation of the demand function:

(p - p₁)/(q - q₁) = (q₂ - q₁)/(p₂ - p₁).

(p - 485)/(q - 3000) = (465 - 485)/(3500 - 3000).

(p - 485)/(q - 3000) = (-20)/(500).

(p - 485)/(q - 3000) = -1/25.

25*(p - 485) = -1*(q - 3000).

25p - 12125 = -q + 3000.

25p + q = 15125.

q = 15125 - 25p. (Demand Equation).

Second, find the supply equation. It is given that the suppliers will not sell the product below or at the price of $300. Therefore, (q₁, p₁) = (0, 300). Also, the suppliers will sell 2000 units if the price is $525. Therefore, (q₂, p₂) = (2000, 525). Since it is mentioned that supply equation is linear, therefore:

(p - p₁)/(q - q₁) = (q₂ - q₁)/(p₂ - p₁).

(p - 300)/(q - 0) = (525 - 300)/(2000 - 0).

(p - 300)/(q) = (225)/(2000).

(p - 300)/(q) = 9/80.

80*(p - 300) = 9*(q).

80p - 24000 = 9q. (Supply Equation).

Equilibrium exists when demand = supply. This means that the demand and the supply equations have to be solved simultaneously. Therefore, put demand equation in supply equation:

80p - 24000 = 9(15125 - 25p).

80p - 24000 = 136125 - 225p.

305p = 160125.

p = $525.

Put p = $525 in demand equation:

q = 15125 - 25p.

q = 15125 - 25(525).

q = 15125 - 13125.

q = 2000 units.

To summarize:

Demand Equation: q = 15125 - 25p!!!

Supply Equation: 80p - 24000 = 9q!!!

Equilibrium Price: $525!!!

Equilibrium Quantity: 2000 units!!!

8 0
3 years ago
Something on sale for $725. The original price was $1299. To the nearest tenth of a percent, what was the rate of discount?
ElenaW [278]

Answer:

44.2%

Step-by-step explanation:

Rate of discount = (difference in prices / original price) x 100

Difference in price = $1299 - $725 = $574

Original price = $1299

($574 / $1299) x 100 = 44.187837%

the tenth is the first number after the decimal place. To convert to the nearest tenth, look at the number after the tenth (the hundredth). If the number is greater or equal to 5, add 1 to the tenth figure. If this is not the case, add zero

the hundredth figure is 8, which is greater than 5. 1 would be added to the tenth figure.

So it becomes 44.2%

4 0
2 years ago
Write an equation for the nth term of the arithmetic seqeuence. Then find a10 100,110,120,130...​
elixir [45]

Answer:

Step-by-step explanation:

N= 100+n(10)

8 0
2 years ago
Shikha has quiz scores of 27, 25, 24, 26 and 25 this term. If she gets a score of 25 and 28, which part of the data( mean, media
forsale [732]

Answer:

mean and range

arrangement before: 24,25,25,26,27

arrangement after: 24,25,25,25,26,27,28

mean before: (27+25+24+26+25)/5 = 25.4

mean after: (27+25+24+26+25+25+28))/5 = 25.7

median before: 25

median after: 25

mode before: 25

mode after: 25

range before: 24 to 27

range after: 24 to 28

hence, the mean and range were affected while the median and mode remained unchanged.

7 0
2 years ago
Gerald walks 1 km in 15 min. Express as a unit rate and explain step by step please
Simora [160]
The rate is 1km/15min

It's a fraction where the denominator is 15 minutes.
To make it a unit rate, we need to make the denominator 1.

A unit rate would be 4 km / hour.
5 0
3 years ago
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