Answer:
Population Mean = 2.0
Population Standard deviation = 0.03
Step-by-step explanation:
We are given that the inspector selects simple random samples of 30 finished products and computes the sample mean product weight.
Also, test results over a long period of time show that 5% of the values are over 2.1 pounds and 5% are under 1.9 pounds.
Now, mean of the population is given the average of two extreme boundaries because mean lies exactly in the middle of the distribution.
So, Mean,
=
= 2.0
Therefore, mean for the population of products produced with this process is 2.
Since, we are given that 5% of the values are under 1.9 pounds so we will calculate the z score value corresponding to a probability of 5% i.e.
z = -1.6449 {from z % table}
We know that z formula is given by ;
~ N(0,1)
-1.6449 =
⇒
⇒
0.0608 *
{as sample size is given 30}
⇒
= 0.03 .
Therefore, Standard deviation for the population of products produced with this process is 0.0333.
The value of this account in 10 years is given by the formula:
FV = P*(1+r)^t
where FV is the future value in the account after 10 years(to be calculated)
P is the principal invested at the beginning
r is the interest rate and
t is the time horizon in years
Given, Invested Amount (P) = 20,000
Interest rate (r) = 5.5% = 0.055
Time horizon (t) = 10 years = 10
Substituting the formula, FV = 20,000*(1+0.055)^10 = 20,000*1.055^10 = 20,000*1.708144458 = 34,162.89
The value of this account after 10 years =$34,162.89 (Rounded to the nearest cent)
Answer:
It is ( - 0.25)
Step-by-step explanation:
I hope that is useful for you :)
Answer:
QR = 3
Step-by-step explanation:
given that Q is on the segment PR , then
PQ + QR = PR ( substitute values )
16 + QR = 19 ( subtract 16 from both sides )
QR = 3