3 years ago

2.7squared add 3.9squared to one decimal place

Mathematics

1 answer:

katrin [286]3 years ago

5 0

$2.7^2=2.7\cdot2.7=7.29\\\\3.9^2=3.9\cdot3.9=15.21\\\\2.7^2+3.9^2=7.29+15.21=\boxed{22.50=22.5}$

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Find the value of Y<br> .....

vekshin1

Answer:

$y = 6 \sqrt{3} \: units$

Step-by-step explanation:

In order to find the value of y, first we need to find the length of the perpendicular dropped from one of the vertices of the triangle to its opposite side.

By geometric mean theorem:

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$=\sqrt{9\times 3}$

$=\sqrt{27}\: units$

Next, by Pythagoras theorem:

${y}^{2} = {9}^{2} + {( \sqrt{27} )}^{2} \\ \\ {y}^{2} = 81 + 27 \\ \\ {y}^{2} = 108 \\ \\ y = \sqrt{108} \\ \\ y = \sqrt{36 \times 3} \\ \\ y = \sqrt{ {6}^{2} \times 3} \\ \\ y = 6 \sqrt{3} \: units$