A=h/2(a+b)
A=h/2a+2b
A(2a+2b)=h
<span>Let makes the table neater. event D= 100m, even E=800m
(Event D) (Event E)
A won the race (Event A) 30 50
B won the race (Event B) 60 25
A and B tied (Event T) 10 25</span>
B did not win the race today. What length of the race was it more likely to have been? The question is asking in what event did the chance of B did not win(lose + ties) is more likely. Then, you need to determine the chance for B did not win <span>in both race.
Chance of B </span>did not win <span>100-m= 30+10/10=40%
</span>Chance of B did not win 800-m= 50+25/10=75%
The difference would be 75%-40%=35% more likely to lose 800-m race
Answer:
$95
Step-by-step explanation:
hope this helps
1st number is x
then the other will be 3x
3x+x=24
4x=24
x=6-first number
2nd is 3*6=18