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Nataly_w [17]
3 years ago
6

What is the main function of mitochondria?

Chemistry
1 answer:
navik [9.2K]3 years ago
8 0
Im like 90% sure it’s energy
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Which of the following elements has the lowest ionization energy? Rb Sr Cs Ba Xe
Misha Larkins [42]
Its been almost a year since i've been in chemistry, so sorry if its not right. Cs, Ba, Rb, Sr, Xe. I think that the levels of ionozation increase from the bottom left corner of the periodic table and increase as you go up and to the right
5 0
3 years ago
What are the 3 main points of the kinetic molecular theory of gases
tigry1 [53]

Answer:

No energy is gained or lost when molecules collide. The molecules in a gas take up a negligible (able to be ignored) amount of space in relation to the container they occupy. The molecules are in constant, linear motion.

Explanation:

Hope this helps!

5 0
3 years ago
Consider the following first order decomposition reaction with a half-life of 65 seconds at a given temperature:
katrin [286]

Answer:

130

Explanation:

This is because that 3atm of N2O4 is used up for the 6atm of NO2, so 1 atm N2O4 is left. Resulting in In(1/4).

6 0
3 years ago
7. A spontaneous reaction occurs when the sign of free energy IS
il63 [147K]

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positive

Explanation:

3 0
2 years ago
How many molecules are in 7.62 L of CH4, at 87.5°C and 722 torr
pickupchik [31]

Answer: There are 1.469 \times 10^{23} molecules present in 7.62 L of CH_4 at 87.5^{o}C and 722 torr.

Explanation:

Given : Volume = 7.62 L

Temperature = 87.5^{o}C = (87.5 + 273) K = 360.5 K

Pressure = 722 torr

1 torr = 0.00131579

Converting torr into atm as follows.

722 torr = 722 torr \times \frac{0.00131579 atm}{1 torr}\\= 0.95 atm

Therefore, using the ideal gas equation the number of moles are calculated as follows.

PV = nRT

where,

P = pressure

V = volume

n = number of moles

R = gas constant = 0.0821 L atm/mol K

T = temperature

Substitute the values into above formula as follows.

PV = nRT\\0.95 atm \times 7.62 L = n \times 0.0821 L atm/mol K \times 360.5 K\\n = \frac{0.95 atm \times 7.62 L}{0.0821 L atm/mol K \times 360.5 K}\\= \frac{7.239}{29.59705}\\= 0.244 mol

According to the mole concept, 1 mole of every substance contains 6.022 \times 10^{23} atoms. Hence, number of atoms or molecules present in 0.244 mol are calculated as follows.

0.244 mol \times 6.022 \times 10^{23}\\= 1.469 \times 10^{23}

Thus, we can conclude that there are 1.469 \times 10^{23} molecules present in 7.62 L of CH_4 at 87.5^{o}C and 722 torr.

5 0
3 years ago
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