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Rasek [7]
1 year ago
7

how did the gross colors (continuous spectrum imparted to the flame by the metal ion solutions compare with the individual spect

ral lines for each element? does the gross color result from a combination of spectral lines or from one particularly intense spectral line? use some online sources to find the answer.
Chemistry
1 answer:
Anna35 [415]1 year ago
7 0

The gross colors can be imparted to the flame by the metal ion solutions .

1.To serve as an excitation source, turn on a Bunsen burner.

2. Perform flame tests on the chloride solutions of Li+, Na+, K+, Ca2+, Sr2+, and Ba2+ as instructed by your lab instructor. Wearing the unique glass blower glasses, take note of the obscene hue that each ion contributes to the flame. With one exception: in order to view the sodium flame, you must remove the special glasses that suppress sodium emissions.

3. Obtain two unidentified answers and note their numerical values. Using the ugly hue the solution gives the flame as a guide, identify the metal ions that are present.

One of the six ions you tested will make up the particle.

To know more about continuous spectrum, please refer:

brainly.com/question/28032005

#SPJ4

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(a) Find ΔS°rxn for the formation of Cu2₂O(s) from its elements.
Strike441 [17]

-75.6 Jmol^{-1}K^{-1} is the ΔS°rxn for the formation of Cu₂O(s) from its elements.

WHAT IS  ΔS°rxn FOR THE REACTION ?

The direction of spontaneous change is the direction in which total entropy increases. Total entropy change, also called the entropy change of the universe, is the sum of the entropy change of a system and of its surroundings

Standard entropy change of below reaction (ΔS°_{rxn})

2Cu(s) + \frac{1}{2} O_2(g) --------- > Cu_2O      ∴ ΔH°_{rxn} = - 168.6 KJ/mol

Now, \Delta S^o_{rxn} = S^o_{(products)} - S^o_{(reactants)}

                   = S^o_{Cu_2 O(s)} - [2 * S^o_{Cu(s)} + \frac{1}{2}(S^o_{O_2(g)}]

                   = (93.1 J/molK)- [2 * 133.1 + \frac{1}{2}(205.0)]J/molK

                   = - 75.6 J/molK

Thus, -75.6 J/mol K is the ΔS°rxn for the formation.

Learn more about ΔS°rxn FOR THE REACTION are:

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3 0
2 years ago
What is the pressure, in mm Hg, of 2.50 moles of an ideal gas if it has a volume of 50.0 liters when the temperature is 27.0° C?
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Use the ideal gas law:
<em>PV=nRT
</em>p = pressure
v = volume
n = number of moles of sample
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T = Temp in Kelvin

Now we substitute while simultaneously solving for P(pressure)
P = (nRT)/V
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P = Now it's your turn.
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Explanation:

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