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Svet_ta [14]
3 years ago
10

Calculate the ph of a 0.005 m solution of potassium oxide k2o

Chemistry
1 answer:
Alecsey [184]3 years ago
3 0
First, we have to see how K2O behaves when it is dissolved in water:

K2O + H20 = 2 KOH

According to reaction K2O has base properties, so it forms a hydroxide in water.
For the reaction next relation follows:

c(KOH) : c(K2O) = 1 : 2

So,

c(KOH)= 2 x c(K2O)= 2 x 0.005 = 0.01 M = c(OH⁻)

Now we can calculate pH:

pOH= -log c(OH⁻) = -log 0.01 = 2

pH= 14-2 = 12




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Answer:

109.09°C

Explanation:

Given that:

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On the other hand; the mass of water = (M__2})= Density*Volume

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\Delta T_{boiling} =  100°C + 17.56 × 0.512

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