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3 years ago

Calculate the ph of a 0.005 m solution of potassium oxide k2o

1 answer:

3 0

First, we have to see how K2O behaves when it is dissolved in water:

K2O + H20 = 2 KOH

According to reaction K2O has base properties, so it forms a hydroxide in water.
For the reaction next relation follows:

c(KOH) : c(K2O) = 1 : 2

So,

c(KOH)= 2 x c(K2O)= 2 x 0.005 = 0.01 M = c(OH⁻)

Now we can calculate pH:

pOH= -log c(OH⁻) = -log 0.01 = 2

pH= 14-2 = 12

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Which bodies of water in the list are found to the west of the Philippines?

bogdanovich [222]

Answer:

South China sea

Explanation:

To the west is the South China Sea, to the east the Philippine Sea and the Pacific Ocean, and to the south the Celebes Sea (or Sulawesi Sea).

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3 years ago

What do the elements within a "period" have in common? (pick one)

Gnesinka [82]

Answer:

All of the elements in a period have the same number of atomic orbitals. For example, every element in the top row (the first period) has one orbital for its electrons. All of the elements in the second row (the second period) have two orbitals for their electrons.

Explanation:

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3 years ago

Read 2 more answers

What are the formal charges of both chlorines and iodine in icl2?

sergejj [24]

Answer:

Explanation:

Formal charge of ICl₂⁻

Formal charge = group no - ( no of non bonding electrons +no of bonds)

In I there are 7 electrons in outermost orbit . If we add one more electrons due to - ve charge on the ion , it becomes eight . This centrally placed iodine forms two single bond with two chlorine atoms on either side.

Each of chlorine atoms also contains 7 valance electrons like iodine.

So formal charge of chlorine

= group no - ( no of non bonding electrons +no of bonds)

= 7 - ( 6 + 1 )

= 0

So formal charge of iodine

= group no - ( no of non bonding electrons +no of bonds)

= 7 - ( 5 + 2 )

Formal charge of ICl₂⁺

In this case , central iodine will have only 6 valence electrons due to absence one electron.

So formal charge of chlorine in ICl₂⁺

= group no - ( no of non bonding electrons +no of bonds)

= 7 - ( 6 + 1 )

= 0

formal charge of iodine in in ICl₂⁺

7 - ( 4 + 2)

= 1

6 0

4 years ago

Identify the gas law that applies to the following scenario: A 36.5 liter balloon holding 2.9 moles of carbon dioxide leaks. If

jarptica [38.1K]

Answer:

Avogadro's Law; 15.1L

Explanation:

Boyle's Law- Pressure and volume are inversely related, so an increase in pressure= decrease in volume. We see this in the equation P1V1=P2V2.

Charle's Law- Gas expands/increases in volume when temperature increases, so they are proportional. We see this in the formula $\frac{V1}{T1} = \frac{V2}{T2}$ .

Guy-Lussac's Law- As temperature increases, pressure increases, so they are proportional. We see this in the formula $\frac{P1}{T1} = \frac{P2}{T2}$ .

Avogadro's Law- There are equal amount of volume have an equal amount of moles, so they are proportional. We see this in the formula $\frac{V1}{n1} = \frac{V2}{n2}$ .