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irina1246 [14]
3 years ago
11

Can y’all please help me? :,)

Mathematics
1 answer:
Step2247 [10]3 years ago
7 0

Answer:

sorry but i cant answer that quiestion

You might be interested in
:
Degger [83]

Let x = pounds of $12 per pound coffee

then

20-x = pounds of $9 per pound coffee

.

12x + 9(20-x) = 10(20)

12x + 180 - 9x = 200

3x + 180 = 200

3x = 20

x = 20/3

x = 6 and 2/3 pounds of $12 per pound coffee

.

Amount of $9 per pound coffee:

20-x = 20-20/3 = 60/3 - 20/3 = 40/3

or

13 and 1/3 pounds of $9 per pound coffee

3 0
3 years ago
By what number should-15/56 be divided to get -5/6<br><br>pls pls pls pls I need your help ​
mr_godi [17]

Answer:

The desired divisor is n = 21

Step-by-step explanation:

Let that number be n.  Then:

-15/56        -5

---------- = ---------

     n            6

Through cross-multiplication we get:

(-15/56)*6 = -5n, which reduces to:

(-15)(7) = -5n, or 3(7) = n

The desired divisor is n = 21

6 0
3 years ago
Which of these is equivalent to 1 over x to the power of 5 ? 1 fifth x negative x to the power of 5 x to the power of 5 x to the
Kisachek [45]

Answer:

x^-5 = x to the power of negative 5

Step-by-step explanation:

Which of these is equivalent to 1 over x to the power of 5 ?

Mathematically this is expressed as

(1/x)⁵

We have a rule when it comes to expressing power

(1/a)^b = a^-b

Hence, applying this rule to our question

(1/x)⁵ = (1/x)^5

= x^-5

This is written in words as:

x to the power of negative 5

5 0
3 years ago
Listed below are the overhead widths​ (in cm) of seals measured from photographs and the weights​ (in kg) of the seals. Construc
Anarel [89]

Answer and Step-by-step explanation: Scaterplot is a type of graphic which shows the relationship between to variables. In this question, you want to determine if there is a linear relationship between overhead widths of seals and the weights. So, the hypothesis are:

H₀: no linear correlation;

H₁: there is linear correlation;

In this hypothesis test, to reject H₀, the correlation coefficient r of the data set has to be bigger than the critical value from the table.

With α = 0.05 and n = 6, the critical value is 0.811.

The linear correlation is calculated as:

r = n∑xy - ∑x.∑y / √[n∑x² - (∑x)²] [n∑y² - (∑y)²]

r = \frac{6.9632 - 51.1108}{\sqrt{6.439 - (51^{2} )}.6.14482 - (1108^{2} ) }

r = 0.9485

Since r is bigger than the critical value, H₀ is rejected, which means there is enough evidence to conclude that there is linear correlation between overhead widths and the weights.

In the attachments is the scaterplot of the measurements, also showing the relationship.

5 0
4 years ago
PLEASE HELPP IT IS SUPER EASY
Rashid [163]

Q- 24.9

R- 7.3

S- -41.5

T- 6.3

Hope this helps❤️

3 0
3 years ago
Read 2 more answers
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