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irina1246 [14]
3 years ago
11

Can y’all please help me? :,)

Mathematics
1 answer:
Step2247 [10]3 years ago
7 0

Answer:

sorry but i cant answer that quiestion

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Ella has a box of chocolate candies. She gives 1/3 of the candies to her sister, 4 to her brother, and eats the remaining 12 can
tatyana61 [14]

Answer:

24 candies originally

Step-by-step explanation:

Add the 4 to how many you had left, then think about that number, 16, and what goes into 16 evenly 2 times? 8 and originally she gave away 1/3 of the box and if you were to add another 8 to the box it would be 24 divided by 1/3, -,-4,= 12.

3 0
3 years ago
In the diagram, the measure of angle 8 is 124°, and the measure of angle 2 is 84°.
Darina [25.2K]

Answer:

(A) 56 on ed genuity

Step-by-step explanation:


3 0
3 years ago
Read 2 more answers
Whitney kicks a football off the ground. The height, h , in feet, of the football above the ground after t seconds is given by h
malfutka [58]

Answer:

<em>after 4seconds</em>

Step-by-step explanation:

Given the height, h , in feet, of the football above the ground after t seconds expressed by h ( t ) = − 8 t^2 + 32 t, the height of the ball on the ground is 0feet.

Substitute h(t) = 0 into the expression and calculate t;

h ( t ) = − 8 t^2 + 32 t

0 = − 8 t^2 + 32 t

8t² = 32t

8t = 32

Divide both sides by 8

8t/8 = 32/8

<em>t = 4s</em>

<em>Hence the football hits the ground after 4seconds</em>

5 0
3 years ago
What is the solution ? Please help with this !!
FromTheMoon [43]

Answer:

the answer is c

Step-by-step explanation:

see picture

7 0
3 years ago
Evaluate the surface integral S F · dS for the given vector field F and the oriented surface S. In other words, find the flux of
Maru [420]

Parameterize S{/tex] by[tex]\vec s(u,v)=u\,\vec\imath+v\,\vec\jmath+(8-u^2-v^2)\,\vec k

with 0\le u\le1 and 0\le v\le1.

Take the normal vector to S to be

\vec s_u\times\vec s_v=2u\,\vec\imath+2v\,\vec\jmath+\vec k

Then the flux of \vec F across S is

\displaystyle\iint_S\vec F\cdot\mathrm d\vec S=\int_0^1\int_0^1\vec F(x(u,v),y(u,v),z(u,v))\cdot(\vec s_u\times\vec s_v)\,\mathrm du\,\mathrm dv

=\displaystyle\int_0^1\int_0^1(uv\,\vec\imath+v(8-u^2-v^2)\,\vec\jmath+u(8-u^2-v^2)\,\vec k)\cdot(2u\,\vec\imath+2v\,\vec\jmath+\vec k)\,\mathrm du\,\mathrm dv

=\displaystyle\int_0^1\int_0^1\bigg(2u^2v+(u+2v^2)(8-u^2-v^2)\bigg)\,\mathrm du\,\mathrm dv=\boxed{\frac{1553}{180}}

6 0
3 years ago
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