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Solve the initial value problem:
dy——— = 2xy², y = 2, when x = – 1. dxSeparate the variables in the equation above:

Integrate both sides:


Take the reciprocal of both sides, and then you have

In order to find the value of
C₁ , just plug in the equation above those known values for
x and
y, then solve it for
C₁:
y = 2, when
x = – 1. So,


Substitute that for
C₁ into (i), and you have

So
y(– 2) is

I hope this helps. =)
Tags: <em>ordinary differential equation ode integration separable variables initial value problem differential integral calculus</em>
No the value of functions are not same .
What is function in math?
- A quantitative expression, rule, or law that describes the link between an independent variable and a dependent variable (the dependent variable).
- In mathematics, functions occur widespread, and they are essential for defining physical links in the sciences.
- A function is a type of rule that generates one output for a single output.
- This is represented by the equation y=x2. Any inputs for x result in an output for y. Given that x is the input value, we would state that y is a result of x.
- 5 × ( -5)⁻⁹ = -5 × 1/-5⁹ ⇒ 1/5⁸ = 1/390625
[ -5 × (-5)]⁻⁹ = [25]⁻⁹ = 1/25⁹ = 1/3814697265625
No the value of functions are not same .
Learn more about function
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Let's make it an expression.
Three half's= 3/2 Plus= + one fifth= 1/5
We need to turn 3/2 and 1/5 so that they have the same denominator. Let's use 10.
3/2→15/10 1/5→2/10
15/10+2/10=17/10=1 7/10
So, three half's plus one fifth is 1 7/10.
Answer:
The answer is probably A
Step-by-step explanation:
Its domain is the only one of these that contain -2, which is a real number.
EMERGENCY CORRECTION: THIS IS WRONG AND I'M TOO ST*PID TO FIGURE OUT THE REAL ANSWER I'M SORRY