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natka813 [3]
3 years ago
11

Ok sooo I need help I don’t understand this lol

Physics
1 answer:
Burka [1]3 years ago
3 0

Answer:

I dont either but I'm sorry and hopefully you figured it out

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A simple pendulum consisting of a bob of mass m attached to a string of length L swings with a period T. If the pendulum is take
Juli2301 [7.4K]

To solve this problem we will use the definition of the period in a simple pendulum, which warns that it is dependent on its length and gravity as follows:

T =2\pi \sqrt{\frac{L}{g}}

Here,

L = Length

g = Acceleration due to gravity

We can realize that 2 \pi is a constant so it is proportional to the square root of its length over its gravity,

T \propto \sqrt{\frac{L}{g}}

Since the body is in constant free fall, that is, a point where gravity tends to be zero:

g \rightarrow 0 \Rightarrow T \rightarrow \infty

The value of the period will tend to infinity. This indicates that the pendulum will no longer oscillate because both the pendulum and the point to which it is attached are in free fall.

5 0
3 years ago
If this experiment is repeated at a place3 meters above the sea level the acceleration due to gravity is expected to
weqwewe [10]

The question doesn't describe any experiment.  If the same experiment is repeated, no matter how many times, the acceleration due to gravity will remain the same as it was during the non-existent original experiment, and will have no effect on anything.

8 0
3 years ago
How to calculate the angle of a resultant<br>​
stiv31 [10]

Answer:

The direction angle θ of the resultant in the Polar (positive) specification is then θ = α + 60°. The Law of Cosines is used to calculate the magnitude (r) and the Law of Sines is used to calculate the angle (α).

3 0
3 years ago
What is the frequency of a sound wave directly related to?
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8 0
3 years ago
A proton moving with a velocity of 4.0 × 104 m/s enters a magnetic field of 0.20 t. if the angle between the velocity of the pro
svlad2 [7]

Answer:

Magnitude of the force on proton = F = 1.1085 × 10^-15 N

Explanation:

Charge on proton = q = 1.60 × 10^-19 C

Velocity of proton = V = 4.0 × 10^4 m/s

Magnetic field = B = 0.20 T  

Angle between V and B = θ = 60

We know that,  

F = qVBsin θ = (1.60 × 10^-19)( 4.0 × 10^4)( 0.20)sin(60)

F = 1.1085 × 10^-15 N    

8 0
3 years ago
Read 2 more answers
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