Question

A truck undergoes a constant acceleration of 2.0 meters/second2 on a highway that slopes upward at an angle of 30.0° to the horizontal. What is the magnitude of the horizontal component of the acceleration?

Answer 1

The horizontal component is    2.0 cos(30°) = 1.732 m/s²

The vertical component is        2.0 sin(30°) = 1 m/s²

Answer 2

Answer: The magnitude of the horizontal component of the acceleration is $1.732 m/s^2$

Explanation:

Acceleration of the truck = $2.0m/s^2$

Angle of the slope on which truck is moving = $30^o$

On splitting the resultant acceleration into vertical component and horizontal component

Vertical components = $asin\theta=asin 30^o=2.0m/s^2\times \frac{1}{2}2.0m/s^2\times 0.5=1.0m/s^2$

Horizontal components =$acos\theta=acos 30^o=2.0 m/s^2\times \frac{\sqrt{3}}{2}=2.0\times 0.866=1.732 m/s^2$

The magnitude of the horizontal component of the acceleration is $1.732 m/s^2$