Answer:
0.00158 A
Explanation:
A = Area of loop = 7.8 cm²
= Final magnetic field = 3.2 T
= Initial magnetic field = 0.5 T
R = Resitance = 
The emf is given by

The current is given by

The resulting induced current in the loop is 0.00158 A
Glucose turns into glycogen
a) E=Nt=100*(4*3600)=1440000 J
b) E=1200*(5*60)=360000 J
c) Q=E*(100-1.8)/100=1414080 J
Answer:
a) v= 2.1 m/s
b) ω = 0.807 rad/s
Explanation
Conceptual analysis :
The dog and the merry-go- round describes a circular motion, then, the following formulas apply :
Formula (1)
v = ω *r Formula (2)
Where:
: Centripetal acceleration(m/s²)
v: linear speed or tangential (m/s)
r : radius of the circle (m)
ω : angular speed ( rad/s)
Data
r= 2.6 m
= 1.7 m/s²
Problem develpment
a) We replace data in the formula 1 to calculate the dog's linear speed(v):


v= 2.1 m/s
b)We replace data in the formula 2 to calculate the angular speed of the merry-go- round (ω).
v = ω *r
2.1 = ω *2.6
ω = 2.1/2.6
ω = 0.807 rad/s