A = 1/2bh
40 = 1/2 x^2
x^2 = 80
x = 8.9
Answer:
(1)0.39
(2)0.14
(3)0.21
(4)0.26
Step-by-step explanation:
John makes 35% of his free throw shots.
- The probability that John makes his shot =0.35
- The probability that John misses his shot =1-0.35=0.65
Sue makes 40% of her free throw shots.
- The probability that Sue makes her shot =0.4
- The probability that Sue misses her shot =1-0.4=0.6
(1)John and sue both miss their shots
P(John and sue both miss their shots)
=P(John miss his shot) X P(Sue misses her shot)
=0.65 X 0.6 =0.39
(2)John and Sue both make their shots
P(John and Sue both make their shots)
=P(John makes his shot) X P(Sue makes her shot)
=0.35 X 0.4=0.14
(3)John makes his shot and Sue misses hers
P(John makes his shot and Sue misses hers)
=P(John makes his shot) X P(Sue misses her shot)
=0.35 X 0.6=0.21
(4)John misses his shot and Sue makes hers
P(John misses his shot and Sue makes hers)
=P(John miss his shot) X P(Sue makes her shot)
=0.65 X 0.4 =0.26
Answer:
Step-by-step explanation:
Answer:
Option B
Step-by-step explanation:
Only lines which are parallel to the line which connects the given two points will neve r intersect,
parallel line has same slope
the slope of the line which connects the given two points is, 5/2
and the line is option B also has the same slope, so those two lines will never intersect each other.
Answered by GAUTHMATH
9514 1404 393
Answer:
1.63 cm (across the centerline from release)
Step-by-step explanation:
If we assume time starts counting when we release the weight from its fully-extended downward position, then the position at 1.15 seconds can be found from ...
h(t) = -7cos(2πt/4)
h(1.15) = -7cos(π·1.15/2) = -7(-0.233445) ≈ 1.63412 . . . cm
That is, 1.15 seconds after the weight is released from below the resting position, it will be 1.63 cm above the resting position.
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If it is released from <em>above</em> the resting position, it will be 1.63 cm <em>below</em> the resting position at t=1.15 seconds.
