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levacccp [35]
3 years ago
6

Which table shows a linear function?​

Mathematics
1 answer:
Sidana [21]3 years ago
6 0
I can’t tell which one until I see the equation
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a man pays 330 each month for his gym membership what is the change in the amount of money in his account after two thirds of a
olasank [31]

\dfrac{\$330}{1\,month}\times\dfrac{12\,month}{1\,year}\times\dfrac{2}{3}\,year\\\\=\$2640

The account will have decreased by $2640 after 2/3 year.

6 0
4 years ago
Please help I will give brainiest
vovikov84 [41]

Answer:

4

Step-by-step explanation:

The constant of proportionality is what determines the relationship between y and x. If t is the constant of proportionality then an example is y = tx .

So 4 is the constant of proportionality

7 0
3 years ago
Read 2 more answers
What is the point slope form of the line with slope −37 that passes through the point (5, 8) ?
Nonamiya [84]

The equation for point slope form is written as :

y - y1 =m(x-x1)

M is the slope which is given as -37

The given point would be X1 and y1, where X1 is 5 and y1 is 8.

The equation becomes:

y - 8 = -37(x -5)

7 0
3 years ago
Read 2 more answers
HELP ASAP!
pychu [463]
C. 36

all you have to do is each side given by 10
5 0
3 years ago
CosA + cosB - cosC = -1 + 4cosA/2 cosB/2 sinC/2
Lubov Fominskaja [6]

Answer:

Step-by-step explanation:

(cos A+ cos B)-cos C

=2cos \frac{A+B}{2}cos \frac{A-B}{2}-cos C~~~...(1)\\A+B+C=180\\A+B=180-C\\\frac{A+B}{2}=90-\frac{C}{2}\\cos \frac{A+B}{2}=cos(90-\frac{C}{2})=sin \frac{C}{2}\\cos C=1-2sin^2\frac{C}{2}\\(1)=2 sin \frac{C}{2} cos \frac{A-B}{2}-1+2sin^2\frac{C}2}\\=2sin\frac{C}{2}[cos \frac{A-B}{2}+sin \frac{C}{2}]-1~~~...(2)\\\\now~again~A+B+C=180\\C=180-(A+B)\\sin\frac{C}{2}=sin(90-\frac{A+B}{2})=cos \frac{A+B}{2}\\(2)=2sin\frac {C}{2}[cos \frac{A-B}{2}+cos \frac{A+B}{2}]-1\\

=-1+2sin\frac{C}{2}*2cos \frac{\frac{A-B}{2} +\frac{A+B}{2} }{2} cos \frac{\frac{A-B}{2} -\frac{A+B}{2} }{2} \\=-1+4sin\frac{C}{2} cos \frac{A}{2} cos\frac{-B}{2} \\=-1+4 cos \frac{A}{2} cos \frac{B}{2} sin \frac{C}{2}\\(cos(-B)=cos B)

8 0
4 years ago
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