8(c-12)=40 that gonna be equal to 8c-96=-40 or 8c=-40+96 ,8c =56 divide both sides by 8 that equal to 7.....
3/4=15
let,
total mass is x
x=4×15/3
=20 kg
so, total mass = 20 kg
=2×20/5
=2×4
=8 kg
Hope this helps!
Answer:
Step-by-step explanation:
If the price is supposed to be dropping with each year, maybe your year/price chart would reflect that. Seems to me that the price rose between 2015 and 2016 and even by 2017 the value was still higher than it was in 2015.
I have no way of knowing how to fix this.
Let's ASSUME that the 2015 price was $71,445 and that the 2016 and 2017 prices are valid.
the decrease between 2015 and 2016 is (71445 - 68640) / 71445 = 0.03926
or 3.926%
the decrease between 2016 and 2017 is (68640 - 65945)/68640 = 0.03926
or 3.926%
so the price each year after new is
p = 71445(1 - 0.03926)ⁿ
or
71445(0.96074)ⁿ
where n is the number of years.
To get the monthly version, we divide the decrease by 12
p = 71445(1 - 0.03926/12)ˣ
or
p = 71445(1 - 0.00327)ˣ
or
p = 71445(0.99673)ˣ
where x is the number of months since new.
This may not be your exact answer, but the same method can be used if you get real numbers.
Answer:
the first step is subtract 4 from both sides
x + 4 > 8
x + 4 - 4 > 8 - 4
Step-by-step explanation:
<h3>
Answer: Choice A</h3>
- Domain: x > 4
- Range: y > 0
========================================================
Explanation:
We want to avoid having a negative number under the square root. Solving 
leads to 
So it appears the domain could involve x = 4 itself; however, if we tried that x value, then we'd get a division by zero error.
So in reality, the domain is x > 4.
-------------
The range of y = sqrt(x) is the set of positive real numbers. So y > 0 is the range for this equation. Shifting left and right does not affect the range, so the range of y = sqrt(x-4) is also y > 0.
We are dividing a positive number (3) over some positive number in the denominator. Overall, the expression 
is positive because positive/positive = positive.
Therefore, the range of the given equation is y > 0
-------------
The graph is shown below. We have a vertical asymptote at x = 4 and a horizontal asymptote at y = 0. The green curve is fenced in the upper right corner (northeast corner).
