1. Given any triangle ABC with sides BC=a, AC=b and AB=c, the following are true :
i) the larger the angle, the larger the side in front of it, and the other way around as well. (Sine Law) Let a=20 in, then the largest angle is angle A.
ii) Given the measures of the sides of a triangle. Then the cosines of any of the angles can be found by the following formula:
a^{2}=b ^{2}+c ^{2}-2bc(cosA)
2.
20^{2}=9 ^{2}+13 ^{2}-2*9*13(cosA) 400=81+169-234(cosA) 150=-234(cosA) cosA=150/-234= -0.641
3. m(A) = Arccos(-0.641)≈130°,
4. Remark: We calculate Arccos with a scientific calculator or computer software unless it is one of the well known values, ex Arccos(0.5)=60°, Arccos(-0.5)=120° etc
Answer: (-2, 11/6)
Step-by-step explanation:
Answer:
$96
Step-by-step explanation:
4 times 10 is 40. 7 times 8 is 56. 40 + 56 = 96
81.4% ≅ 81%. The probability that a customer ordered a hot drink given that he or she ordered a large is 81%.
The key to solve this problem is using the conditional probablity equation P(A|B) = P(A∩B)/P(B). Conditional probability is the probability of one event occurring with some relationship to one or more other events.
Similarly to the previous exercise, P(A∩B) is the probability that a customer order a large hot drink. So, P(A∩B) = 22/100 = 0.22
For P(B), is the probability that a customer order a large drink whether hot or cold. P(B) = 27/100 = 0.27
P(A|B) = 0.22/0.27 = 0.814
multiplying by 100%, we obtain 81.4%
No this is to much work for something that is 5 points to do Na man but I hope this helps you in the future .
