Answer:
x = 1,5, and 2
Step-by-step explanation:
if y=4, then
4 = x+3, x=1
if y=8, then
8 = x+3, x=5
if y=5, then
5 = x+3, x=2
I hope this helps, and please mark me brainliest!
Complete question:
A student throws a heavy ball downward off the top of a building with a speed of 18m/s. The ball reaches a speed of 41m/s just before striking the ground. Neglect drag, find the height of the building.
Answer:
The height of the building is 69.235 m
Step-by-step explanation:
Given;
initial velocity of the ball, u = 18 m/s
final velocity of the ball, v = 41 m/s
The height of the building is equal to distance traveled by the ball downward.
Apply the following kinematic equation;
v² = u² + 2gh
where;
g is acceleration due to gravity
h is height of the building
41² = 18² + 2(9.8)h
1681 = 324 + 19.6h
19.6h = 1681 - 324
19.6h = 1357
h = 1357 / 19.6
h = 69.235 m
Therefore, the height of the building is 69.235 m
For 1.
Solution,
Sides(l)= 3.5
Now,
Perimeter of square=4l
=4*3.5
=14
Then,
Area of square =l^2
=3.5*3.5
=12.25
For 2.
Solution,
Sides(l)=1
Now, perimeter of square =4l
=4*1
=4
Then,
Area of square =l^2
=1*1
=1
For 3.
Solution,
Sides(l)= 20
Now,
Perimeter of square=4l
=4*20
=80
Then,
Area of square =l^2
=20*20
=400
Answer:
141.5
Step-by-step explanation:
because, x=26.5 and y=4 and then, its just plugining it into the equation Im not sure about the x and y but, I took the test and got it right.
