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Eddi Din [679]
3 years ago
6

I have no idea how to do this, so if someone could at least do one of these I’ll be grateful <3

Mathematics
2 answers:
jenyasd209 [6]3 years ago
7 0

Answer:

Answers are below!

Step-by-step explanation:

(2 + g) (8)

= (2 + g) (8)

Add a 8 after the 2, and flip.

= (2)(8) + (g)(8)

= 16 + 8g

= 8g + 16

= (4) (8 + -5g)

Add another 4, then flip.

= (4) (8) + (4) (-5g)

= 32 − 20g

= - 20g + 32

−7 (5-n)

= (−7) (5 + -n)

Add another 7, then flip.

= (−7) (5) + (-7) (-n)

= −35 + 7n

= 7n - 35

Use the distributive property.

a (b + c) = ab + ac

a = 8

b = 2m

c = 1

= 8 × 2m + 8 × 1

Simplify, you get 16m + 8.

Use the distributive property.

a (b + c) = ab + ac

a = 6x

b = y

c = z

= 6xy - 6xz is the answer.

\mathrm{Apply\:the\:distributive\:law}:\quad \\\:a\left(b+c\right)=ab+ac

a=-3,\:b=2b,\:c=2a

=-3\cdot \:2b+\left(-3\right)\cdot \:2a

Apply minus plus rules.

=-3\cdot \:2b+\left(-3\right)\cdot \:2a

Multiply the numbers.

3 x 2 = 6

amid [387]3 years ago
6 0

Answer:

9. -35+7n

10. 16m+8

11. 6xy-6xz

Step-by-step explanation:

You multiplying the terms inside the ( ) by the outside factor.

This is call distributive property, a(b+c)=ab+ac.

Also, a(b+c)=(b+c)a by commutative property.

It also works over the operation subtraction since subtraction is just a disguised addition (addition of the opposite). That is, a(b-c)=ab-ac.

Anyhow, let's look at 9.,10., and 11..

9.

-7(5-n)

(-7)(5-n)

(-7)(5)-(-7)(n)

-35+7n

10.

8(2m+1)

(8)(2m)+(8)(1)

16m+8

11.

6x(y-z)

(6x)(y-z)

(6x)(y)-(6x)(z)

6xy-6xz

Hint on 7. It's like all the other problems. That is, it is equivalent to doing 8(2+g).

If you want comment below, if you want me to check any of yours or if you have any questions.

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The accompanying data came from a study of collusion in bidding within the construction industry. No. Bidders No. Contracts 2 6
viktelen [127]

Answer:

a)

The proportion of contracts involved at most five bidders is 0.667.

The proportion of contracts involved at least five bidders is 0.51.

b)

The  proportion of contracts involved  between five and 10 inclusive bidders is 0.5.

The  proportion of contracts involved  strictly between five and 10 bidders is 0.304.

Step-by-step explanation:

No. bidders    No. contracts     Relative frequency of contracts

2                         6                       6/102=0.0588

3                         20                     20/102=0.1961

4                         24                     24/102=0.2353

5                         18                       18/102=0.1765

6                         13                        13/102=0.1275

7                          7                          7/102=0.0686

8                          5                          5/102=0.049

9                          6                          6/102=0.0588

10                         2                           2/102=0.0196

11                          1                            1/102=0.0098

Total                  102

a)

We have to find proportion of contracts involved at most five bidders.

Proportion of at most 5= Relative frequency 2+ Relative frequency 3+ Relative frequency 4+ Relative frequency 5

Proportion of at most 5=0.0588+ 0.1961+0.2353+0.1765

Proportion of at most 5=0.6667

The proportion of contracts involved at most five bidders is 0.667.

proportion of at least five bidders= proportion≥5= 1- proportion less than 5

Proportion less than 5=0.0588+ 0.1961+0.2353=0.4902

proportion of at least five bidders=1-0.4902=0.5098

The proportion of contracts involved at least five bidders is 0.51

b)

We have to find proportion of contracts involved  between five and 10 inclusive bidders.

Proportion of contracts between five and 10 inclusive= Relative frequency 5+ Relative frequency 6+ Relative frequency 7+ Relative frequency 8+ Relative frequency 9+ Relative frequency 10

Proportion of between five and 10 inclusive=0.1765 +0.1275 +0.0686 +0.049 +0.0588 +0.0196

Proportion of between five and 10 inclusive=0.5

The  proportion of contracts involved  between five and 10 inclusive bidders is 0.5

We have to find proportion of contracts involved  strictly between five and 10 bidders.

Proportion of contracts strictly between five and 10=  Relative frequency 6+ Relative frequency 7+ Relative frequency 8+ Relative frequency 9

Proportion of strictly between five and 10=0.1275 +0.0686 +0.049 +0.0588

Proportion of strictly between five and 10=0.3039

The  proportion of contracts involved  strictly between five and 10 bidders is 0.304.

8 0
3 years ago
A university employs a total of 560 teaching assistants and research assistants. There are three times as many teaching
Scrat [10]

Answer:

170

Step-by-step explanation:

There are three times as many teaching assistants as research assistants. Find the number of research assistants employed by the university. Hence the number of research assistants is 170.

8 0
2 years ago
A coin is tossed, and a standard number cube is rolled. What is the probability that the coin shows heads and the number cube sh
Ainat [17]
So,

Since this is independent probability, the probability of the event above occurring is:
(probability\ of\ heads)(probability\ of\ even\ no.)

First, the probability of landing on heads.
\frac{1}{2}

Now, the probability of rolling an even number.
<u />\frac{3}{6}\ or\  \frac{1}{2}

Plug it into the equation.
\frac{1}{2} * \frac{1}{2} =  \frac{1}{4}

The correct option is C.
7 0
3 years ago
A new cruise ship line has just launched 3 new​ ships: the Pacific​ Paradise, the Caribbean​ Paradise, and the Mediterranean Par
topjm [15]
Let the number of deluxe that Pacific has be x
the number that Caribbean has will be (x+18)
the number that Mediterranean has will be (3x-25)
total b=number of deluxe in the 3 ships will be:
x+(x+18)+(3x-25)
5x-7=928
5x=928+7
x=935/5
x=187
Hence the Pacific has 187, Caribbean has 187+18=205, Mediterranean has (3*187-25)
=534 
6 0
3 years ago
A triangle has a perimeter of 75 inches. Find the length of three sides
Mamont248 [21]

Answer:po6

Step-by-step explanation:

3 0
3 years ago
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