To find the pre image you need to back track on the image. To get to the image you used (x-6,y+8). Now you need to use the exact opposite to get back to the pre image. For this you would change the signs to look like (x+6,y-8). Now we just apply this to (-4,1).
(-4+6,1-8)
(2,-7) should be the pre image point.
68 can go into 757 11 times, the remainder would be 9
757÷68= 11 r 9 or 11 9/68
Answer:
17rx2−23rx−71x+75
Step-by-step explanation:
(17x−23)(xr−4)−(3x+17)
=(17x−23)(xr−4)+−1(3x+17)
=(17x−23)(xr−4)+−1(3x)+(−1)(17)
=(17x−23)(xr−4)+−3x+−17
=(17x)(xr)+(17x)(−4)+(−23)(xr)+(−23)(−4)+−3x+−17
=17rx2+−68x+−23rx+92+−3x+−17
=17rx2+−68x+−23rx+92+−3x+−17
=(17rx2)+(−23rx)+(−68x+−3x)+(92+−17)
=17rx2+−23rx+−71x+75
Yes 2,920 is the correct answer because if you divide 2,920 divided by 8 then you will get 365 days.
