Question

Your friend claims that it is possible to draw a right triangle where the cosine of either angle (theta) is exactly the same value. Is she correct?
A. Yes
B. No​

Answer 1

Answer:

B. No

$Cos \ \theta\neq Cos (90-\theta)\textdegree$

Step-by-step explanation:

-A right angle triangle has two complimentary acute angles and one right angle.

-$\theta$ is usually one of the acute angles and is equivalent to 90º minus it's complimentary acute angle.

-Complimentary angles add up to 90º.

#For complimentary angles:

$Sin \ \theta=Cos \ (90-\theta)\textdegree\\\\Cos \ \theta=Sin(90-\theta)\textdegree\\\\\therefore Cos \ \theta\neq Cos (90-\theta)\textdegree$

The two acute angles cannot have the same Cosine value.

Hence, she's not correct.