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astraxan [27]
2 years ago
11

Ralph’s average score for 5 tests was 82. on four of the tests his scores were 85, 73, 92, 66. what was the fifth test score?

Mathematics
1 answer:
SCORPION-xisa [38]2 years ago
5 0

Answer:

94

Step-by-step explanation:

Let the unknown number be denoted by the variable, x. Also note that, the average can be found by adding all values together and dividing by the amount of values there are.

Set the equation:

(85 + 73 + 92 + 66 + x)/5 = 82

Isolate the variable, x. Note the equal sign, what you do to one side, you do to the other. Simplify first by combining like terms, and then do the opposite of PEMDAS.

PEMDAS is the order of operations, and stands for:

Parenthesis

Exponents (& roots)

Multiplications

Divisions

Additions

Subtractions.

Combine like terms:

(85 + 73 + 92 + 66 + x)/5 = 82

(316 + x)/5 = 82

Next, isolate the x, by multiplying 5 to both sides of the equation:

(316 + x)/5 * 5 = (82) * 5

316 + x = 82 * 5

316 + x = 410

Lastly, subtract 316 from both sides of the equation:

x + 316 = 410

x + 316 (-316) = 410 (-316)

x = 410 - 316

x = 94

94 is the final test score.

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there are 46 2-digit numbers in which the tens digit is greater than the ones digit.

<h3>How many 2-digit numbers are there in which the tens digit is larger than the ones digit?</h3>

A 2-digit number is written as:

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Where a and b are single-digit numbers.

Tens digit and ones digit refers to place values:

a is the tens digit, and b is the ones digit. The numbers with a larger tens digit than the ones digit are:

98, 97, 96, 95, 94, 93, 92, 91, 90, 87, 86, 85, 84, 83, 82, 81, 80, 76, 75, 75, 74, 73, 72, 71, 70, 65, 64, 63, 62, 61, 60, 54, 53, 52, 51, 50, 43, 42, 41, 40, 32, 31, 30, 21, 20, 10.

We can see that there are 46 numbers in that list, so we conclude that there are 46 2-digit numbers in which the tens digit is greater than the ones digit.

If you want to learn more about place values:

brainly.com/question/12386995

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