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3 years ago

The line passes through the point (4,2) and has slope of -1

Mathematics

1 answer:

Ira Lisetskai [31]3 years ago

3 0

Answer:

y-2 = -1(x-4)

Step-by-step explanation:

We know the slope and a point . We can use point slope form

y-y1 = m(x-x1)

y-2 = -1(x-4)

If we want the equation in slope intercept form

Distribute the -1

y-2 = -x+4

Add 2 to each side

y-2+2 = -x+4+2

y = -x+6

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When the temperature of an object increases, what happens to the kinetic energy of the particles in the object?

valentina_108 [34]

C.) It increases ............

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3 years ago

Read 2 more answers

In this graph what is the slope of the line?

sashaice [31]

Answer:

The slope of the line is 10

Step-by-step explanation:

To find the slope, simply identify 2 points on the line. I chose: (1,10) and (2,20)

20-10=10

2-1=1

The slope of the line is 10

To check this answer, just multiply X with 10 and you will always get Y!

7 0

3 years ago

A manufacturer of Christmas light bulbs knows that 10% of these bulbs are defective. It is known that light bulbs are defective

Inessa05 [86]

Answer:

(a) P(X $\leq$ 20) = 0.9319

(b) Expected number of defective light bulbs = 15

Step-by-step explanation:

We are given that a manufacturer of Christmas light bulbs knows that 10% of these bulbs are defective. It is known that light bulbs are defective independently. A box of 150 bulbs is selected at random.

Firstly, the above situation can be represented through binomial distribution, i.e.;

$P(X=r) = \binom{n}{r} p^{r} (1-p)^{2} ;x=0,1,2,3,....$

where, n = number of samples taken = 150

r = number of success

p = probability of success which in our question is % of bulbs that

are defective, i.e. 10%

Now, we can't calculate the required probability using binomial distribution because here n is very large(n > 30), so we will convert this distribution into normal distribution using continuity correction.

So, Let X = No. of defective bulbs in a box

Mean of X, $\mu$ = $n \times p$ = $150 \times 0.10$ = 15

Standard deviation of X, $\sigma$ = $\sqrt{np(1-p)}$ = $\sqrt{150 \times 0.10 \times (1-0.10)}$ = 3.7

So, X ~ N( $\mu = 15, \sigma^{2} = 3.7^{2})$

Now, the z score probability distribution is given by;

Z = $\frac{X-\mu}{\sigma}$ ~ N(0,1)

(a) Probability that this box will contain at most 20 defective light bulbs is given by = P(X $\leq$ 20) = P(X < 20.5) ---- using continuity correction

P(X < 20.5) = P( $\frac{X-\mu}{\sigma}$ < $\frac{20.5-15}{3.7}$ ) = P(Z < 1.49) = 0.9319

(b) Expected number of defective light bulbs found in such boxes, on average is given by = E(X) = $n \times p$ = $150 \times 0.10$ = 15.

5 0

3 years ago

A stadium brings in $16.25 million per year. it pays football-related expenses of $13.5 million and stadium expenses of $2.7 mil

Ganezh [65]

We have that

Profit margin is calculated by finding the net profit as a percentage of the revenue

Profit margin = [Net profit / Revenue]

Net profit= [Revenue-Cost]

we know that

Revenue = $16.25 million

Cost = $13.5 million + $2.7 million

Net profit = [16.25 million - (13.5 million + 2.7 million)]

Net profit = $0.05 million

Profit margin = 0.05 / 16.25

Profit margin = 0.003077 or 0.3077%

3 0

3 years ago

The principal uses a computer to randomly select the name of a student from all the students in

Arlecino [84]

Complete Question

Stillwater Junior High divides students into teams taught by a group of teachers. The table shows the number of students in each team.

Team{Number of Students}

Acers{78}

Blazers{80}

Outbacks{83}

Quasars{77}

Voyagers{82}

Total-400

Answer:

(A)81/399

Step-by-step explanation:

The probability that the Principal selects a voyager on the first try is:

82/400

Since another student is to be selected, the total population has reduced by 1 and the number of voyagers likewise has been reduced by 1.

Therefore:

Probability that another voyager is selected on the second try =

81/399

The correct option is A.

7 0

3 years ago