The mayor is interested in finding a 95% confidence interval for the mean number of pounds of trash per person per week that is
1 answer:
Answer:
(30.09, 32.91)
Step-by-step explanation:
Mean number of pounds of trash = x = 31.5 pounds
Standard deviation = s = 7.8 pounds
Sample size = n = 120
Confidence level = 95%
Since, we are given the sample standard deviation instead of the population standard deviation, we will use t-test to find the confidence interval.
Degrees of freedom = df = n - 1 = 120 - 1 = 119
The t-value associated with 95% confidence interval and df=119 from the t-table comes out to be:
t = 1.98
The formula to calculate the confidence interval is:
Using the values in above expression we get:
Thus, the 95% confidence interval for the mean number of lbs of trash per person per week that is generated in the city is (30.09, 32.91)
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The answers are x=6 or x=-1.
To solve this, we first use the quotient rule for the natural logarithm. It says that ln(x/y) = ln(x) - ln(y). Applying this, we take our original equation,
and rewrite it as
We undo natural log by raising e to both sides:
Once this is canceled we are left with:
If we view this as a proportion, we can cross multiply:
(x-3)(x) = 2(x+3)
Using the distributive property on both sides we have:
x²-3x=2x+6
Cancel the 2x from the right hand side by subtracting:
x²-3x-2x=2x+6-2x
x²-5x=6
Cancel the 6 by subtracting:
x²-5x-6=0
This is easily factorable. We want factors of -6 that sum to -5; -6(1) = -6 and -6+1=-5:
(x-6)(x+1)=0
Using the zero product property, we know either x-6=0 or x+1=0; thus x=6 or x=-1.
To solve this, we first use the quotient rule for the natural logarithm. It says that ln(x/y) = ln(x) - ln(y). Applying this, we take our original equation,
and rewrite it as
We undo natural log by raising e to both sides:
Once this is canceled we are left with:
If we view this as a proportion, we can cross multiply:
(x-3)(x) = 2(x+3)
Using the distributive property on both sides we have:
x²-3x=2x+6
Cancel the 2x from the right hand side by subtracting:
x²-3x-2x=2x+6-2x
x²-5x=6
Cancel the 6 by subtracting:
x²-5x-6=0
This is easily factorable. We want factors of -6 that sum to -5; -6(1) = -6 and -6+1=-5:
(x-6)(x+1)=0
Using the zero product property, we know either x-6=0 or x+1=0; thus x=6 or x=-1.
Answer:
3x×2c+1
Step-by-step explanation:
6x+15 =4c-12