We have to find x and x is the hypotenuse. We use this formula:
hyp²=side²+side²
So:
hyp²=side²+side²
hyp²= 12²+9²
hyp²= 225
hyp²= √225
hyp= 15
Therefore, the hypotenuse is 15 and x is 15.
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Answer:
∠EFG = 48°
Step-by-step explanation:
As FH bisects ∠EFG , ∠EFH = ∠HFG .
We know that ∠EFH = (-5x + 89)° . So ∠HFG = ∠EFH = (-5x + 89)°
Also, ∠HFG + ∠EFH = ∠EFG
=> 2(-5x + 89)° = (61 - x)°
=> -10x + 178 = 61 - x
=> 10x - x = 178 - 61
=> 9x = 117
=> x = 117 / 9 = 13
Putting the value of 'x' in ∠EFG gives :-
(61 - x)° = (61 - 13)° = 48°
Answer: 
Step-by-step explanation:
Rewrite it in the form
, where 

Use Square of Sum: 

Answer:
∴Given Δ ABC is not a right-angle triangle
a= AB = √45 = 3√5
b = BC = 12
c = AC = √45 = 3√5
Step-by-step explanation:
Given vertices are A(3,3) and B(6,9)

AB = 
Given vertices are B(6,9) and C( 6,-3)
= 
BC = 12
Given vertices are A(3,3) and C( 6,-3)

AC² = AB²+BC²
45 = 45+144
45 ≠ 189
∴Given Δ ABC is not a right angle triangle