Omg i am bored so answer and get points will mark as brelenzz

What is the angle of c (∠c) Help immensely I will give brainliest

jeka57 [31]

Answer:

The measure of ∠c is 50°.

Step-by-step explanation:

When it comes to problems like these, there are two types of angles that should be kept in mind: complementary angles and supplementary angles.

Complementary angles are angles that add up to 90° (a right angle). Supplementary angles are angles that add up 180° degrees (a straight angle). A good way to recall this information in layman's terms is to remember this: complements are always right.

So now let's apply what we've learned to the problem. We have a straight angle that is composed of two 65° angles and an unknown C angle. We know that when angles add up to 180°, they're supplementary angles.

If we interpret our problem in algebriac form, we can say that:

65° + 65° + m∠C = 180°

Now we just solve this problem like any other algebriac equation. First, you can combine like terms.

130° + m∠C = 180°

Then, subtract 130° on both sides to isolate our variable.

m∠C = 50°

Now we can safely say that the measure of angle C is 50°.

3 0

3 years ago

In a survey of women in a certain country the mean height was 62.9 inches with a standard deviation of 2.81 inches answer the fo

Natasha2012 [34]

The question is incomplete. The complete question is :

In a survey of women in a certain country ( ages 20-29), the mean height was 62.9 inches with a standard deviation of 2.81 inches. Answer the following questions about the specified normal distribution. (a) What height represents the 99th percentile? (b) What height represents the first quartile? (Round to two decimal places as needed)

Solution :

Let the random variable X represents the height of women in a country.

Given :

X is normal with mean, μ = $62.9$ inches and the standard deviation, σ = $2.81$ inches

Let,

$Z=\frac{X - 62.9}{2.81}$ , then Z is a standard normal

a). Let the $99th$ percentile is = a

The point a is such that,

$$P(X$

$P \left( Z < \frac{a-62.9}{2.81} \right) = 0.99$

From standard table, we get : $P( Z < 2.3263) =0.99$

∴ $\frac{(a-62.9)}{281} = 2.3263$

$a= (2.3263 \times 2.81 ) +62.9$

= 6.536903 + 62.9

= 69.436903

= 69.5 (rounding off)

Therefore, the height represents the $99th$ percentile = 69.5 inches.

b). Let b = height represents the first quartile.

It is given by :

$P( X < b) =0.25$

$P \left( Z < \frac{(b-62.9)}{2.81} \right) = 0.25$

From the standard normal table,

$P( Z < -0.6745) =0.99$

∴ $\frac{(b-62.9)}{2.81}= 0.6745$

$b=(0.6745 \times 2.81) +62.9$

= 1.895345 + 62.9

= 64.795345

= 64.8 (rounding off)

Therefore, the height represents the 1st quartile is 64.8 inches.

8 0

3 years ago

What is the area of this parallelogram?

gavmur [86]

A=AB*DE=(8+4)*7=12*7=84 m^2

A=84 m^2

4 0

4 years ago

Read 2 more answers

Nadia cuts 3 pieces of equal length from 8 yards of ribbon .How is each piece

Volgvan

Your answer is 2.66666667

3 0

3 years ago

Please help me!!!! Help me find the dimensions. :(

Gnom [1K]

The volume, surface area and the ratios of the SA to volume will be as follows:
Volume=πr²h
Area=2πr²+πdh
Ratio of SA to volume=Area/volume
π=3.14
Thus using the above formula:

1.
a]
Radius: 3 inches
Height: 2 inches
Volume=πr²h
volume=π×3²×2=56.52 in³

b]
Area=2πr²+πdh
2×π×3²+π×2×3×2
=56.55+37.68
=94.23 in²

c]
Ratio=area/volume
=94.23/56.52
=1.6672

1.
Radius: 2 inches
Height: 9 inches

a]
V=πr²h
V=3.14*2^2*9
V=113.04 in³

b]
Area=2πr²+πdh
=2*3.14*2^2+3.14*2*2*9
=25.12+113.04
=138.16 in²

c]
Ratio=area/volume
=138.16/113.04
=11/9

3.
Diameter=4 inches
Height= 9 inches

a]
V=πr²h
V=3.14×2²×9
V=113.04

b]
Area=2πr²+πdh
=2*3.14*2^2+3.14*4*9
=25.12+113.04
=138.16 in²

c]
Ratio=area/volume
=138.16/113.04
=11/9

4]
Diameter: 6 inches
Height: 4 inches

a]
Volume=πr²h
=3.14×3²×4
=113.04 in³

b]
Area=2πr²+πdh
=2×3.14×3²+3.14×6×4
=56.52+75.36
=131.88 in²

c] Ratio
131.88/113.04
=7/6

1. For the surface area to volume to be small it means that the area is smaller than the volume, for surface area to volume be larger it means that the surface area is larger than the volume. It is more economical for the surface area to volume to be small because it will mean that small amount of materials make cans with large volume. This means cost of production is cheaper.

2. To evaluate this process let's use one of the dimensions:
Radius: 3 inches
Height: 2 inches:

i. add radius and height:
3+2=5 inches
ii. Multiply radius and height:
3×2=6
iii. Dividing the result from step 1 by the result in step 2:
5/6

iv. Multiply the result from step 3 by 2:
5/6×6
=5
This result does not seem to add up to the result in our earlier ratio. Thus we conclude that Khianna was wrong. This method can't work with 3-D figures.

7 0

4 years ago