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erastovalidia [21]
3 years ago
12

Pls answer all 3 parts

Mathematics
2 answers:
galben [10]3 years ago
6 0

Answer:

a. 14

b. 1

c. 2

Step-by-step explanation:

If there are 4 one point questions and 5 two point questions, then 5 multiplied by two is 10 and adding it to 4 is 14. The quiz would be 14 points total. If you scored 87.5% on the quiz then you would know that you got 12 of the questions correct and you would know that by finding 87.5% of 14 which the equation to do so would be 87.5/100= 0.875, then 0.875* 14= 12.25. If you round 12.25 to the nearest whole number then it's 12. And since you got all the 1 point questions right, then you must of gotten 1 two point question wrong.

I hope this helps!

olganol [36]3 years ago
5 0
Answers
A-14
B-1
C-2
:)
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Write a conditional statement. Write the converse, inverse and contrapositive for your statement and determine the truth value o
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A conditional statement involves 2 propositions, p and q. The conditional statement, is a proposition which we write as: p⇒q,

and read  "if p then q" 



Let p be the proposition: Triangle ABC is a right triangle with m(C)=90°.

Let q be the proposition: The sides of triangle ABC are such that 

|AB|^2=|BC|^2+|AC|^2.


An example of a conditional statement is : p⇒q, that is:

if Triangle ABC is a right triangle with m(C)=90° then The sides of triangle ABC are such that |AB|^2=|BC|^2+|AC|^2


This compound proposition (compound because we formed it using 2 other propositions) is true. So the truth value is True, 


the converse, inverse and contrapositive of p⇒q are defined as follows:

converse: q⇒p
inverse: ¬p⇒¬q (if [not p] then [not q])
contrapositive: ¬q⇒¬p

Converse of our statement:

if The sides of triangle ABC are such that |AB|^2=|BC|^2+|AC|^2
then Triangle ABC is a right triangle with m(C)=90°

True


Inverse of the statement:

if Triangle ABC is not a right triangle with m(C) not =90° then The sides of triangle ABC are not such that |AB|^2=|BC|^2+|AC|^2

True


Contrapositive statement:

if The sides of triangle ABC are not such that |AB|^2=|BC|^2+|AC|^2  then Triangle ABC is not a right triangle with m(C)=90°


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Your friend asks if you would like to play a game of chance that uses a deck of cards and costs $1 to play. They say that if you
gtnhenbr [62]

Answer:

Expected value = 40/26 = 1.54 approximately

The player expects to win on average about $1.54 per game.

The positive expected value means it's a good idea to play the game.

============================================================

Further Explanation:

Let's label the three scenarios like so

  • scenario A: selecting a black card
  • scenario B: selecting a red card that is less than 5
  • scenario C: selecting anything that doesn't fit with the previous scenarios

The probability of scenario A happening is 1/2 because half the cards are black. Or you can notice that there are 26 black cards (13 spade + 13 club) out of 52 total, so 26/52 = 1/2. The net pay off for scenario A is 2-1 = 1 dollar because we have to account for the price to play the game.

-----------------

Now onto scenario B.

The cards that are less than five are: {A, 2, 3, 4}. I'm considering aces to be smaller than 2. There are 2 sets of these values to account for the two red suits (hearts and diamonds), meaning there are 4*2 = 8 such cards out of 52 total. Then note that 8/52 = 2/13. The probability of winning $10 is 2/13. Though the net pay off here is 10-1 = 9 dollars to account for the cost to play the game.

So far the fractions we found for scenarios A and B were: 1/2 and 2/13

Let's get each fraction to the same denominator

  • 1/2 = 13/26
  • 2/13 = 4/26

Then add them up

13/26 + 4/26 = 17/26

Next, subtract the value from 1

1 - (17/26) = 26/26 - 17/26 = 9/26

The fraction 9/26 represents the chances of getting anything other than scenario A or scenario B. The net pay off here is -1 to indicate you lose one dollar.

-----------------------------------

Here's a table to organize everything so far

\begin{array}{|c|c|c|}\cline{1-3}\text{Scenario} & \text{Probability} & \text{Net Payoff}\\ \cline{1-3}\text{A} & 1/2 & 1\\ \cline{1-3}\text{B} & 2/13 & 9\\ \cline{1-3}\text{C} & 9/26 & -1\\ \cline{1-3}\end{array}

What we do from here is multiply each probability with the corresponding net payoff. I'll write the results in the fourth column as shown below

\begin{array}{|c|c|c|c|}\cline{1-4}\text{Scenario} & \text{Probability} & \text{Net Payoff} & \text{Probability * Payoff}\\ \cline{1-4}\text{A} & 1/2 & 1 & 1/2\\ \cline{1-4}\text{B} & 2/13 & 9 & 18/13\\ \cline{1-4}\text{C} & 9/26 & -1 & -9/26\\ \cline{1-4}\end{array}

Then we add up the results of that fourth column to compute the expected value.

(1/2) + (18/13) + (-9/26)

13/26 + 36/26 - 9/26

(13+36-9)/26

40/26

1.538 approximately

This value rounds to 1.54

The expected value for the player is 1.54 which means they expect to win, on average, about $1.54 per game.

Therefore, this game is tilted in favor of the player and it's a good decision to play the game.

If the expected value was negative, then the player would lose money on average and the game wouldn't be a good idea to play (though the card dealer would be happy).

Having an expected value of 0 would indicate a mathematically fair game, as no side gains money nor do they lose money on average.

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Mumz [18]
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