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Svetach [21]
3 years ago
6

Rewrite in standard form ​

Mathematics
2 answers:
Anarel [89]3 years ago
8 0

9514 1404 393

Answer:

  3x -5y = 4

Step-by-step explanation:

The coefficients are mutually prime integers in standard form. Here, a common factor of 8 can be removed from all of them. The result is ...

  3x -5y = 4

Vlad1618 [11]3 years ago
8 0

Answer:

I think it's this ( 40y+32/24) {See Below For More}

Step-by-step explanation:

Move all constant terms to the right-hand-side

24x=32+40y

Move all constant terms to the right-hand-side

X= <u>40y+32</u>

24

The Equation Is Solved With:

X 1 = <u>4</u><u>0</u><u>y</u><u>+</u><u>3</u><u>2</u>

24

Solution Of The Equation:

X1= <u>4</u><u>0</u><u>y</u><u>+</u><u>3</u><u>2</u>

24

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The weights of the apples grown on an orchard are normally distributed. The mean weight has been m0 = 9.500 ounces. Because of t
diamong [38]

Answer:

t(s) is in rejection zone then we reject H₀.

Bad weather indeed make apples weight decrease

Step-by-step explanation:

Normal Distribution

population mean    μ₀   = 9.5 ou

sample size   =  n   =  16  then we should apply t-student table

degree of fredom   df  =  n  - 1     df =  16  -  1    df  = 15

1.-Test  hypothesis

H₀     null  hypothesis                          μ₀   =  9.5    

Hₐ alternative hypothesis                   μ₀  <  9.5

One left tail-test

2.-Confidence level 95 %

α  =  0,05    and   df  = 15    from t-student table we get  t(c)  =  - 1.761

3.-Compute t(s)  

t(s)  =  [ μ  -  μ₀  ] /√s/n         t(s)  = (9.32  -  9.5 )* √16 / 0.18

t(s)  = -  0.18*√16 / 0.18

t(s)  = - 4

4.-Compare  t(s)   and t(c)

t(s) < t(c)     -4  <  - 1.761

Then  t(s)  is in the rejection zone.

5.- Decision

t(s) is in rejection zone then we reject H₀.

Farmer conclude that bad weather make apples weight decrease

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Answer:

458

Step-by-step explanation:

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4xy-3x+8y2-6y 8y-6 please help someone thank you
avanturin [10]

Answer:

x=6, y=2.5

Step-by-step explanation:

6 0
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