in the f(t) = 15000(1.08)ᵗ, which is a form of a compounded interest formula, t = years, so
f(t) = 15000(1.08)¹⁰ , is the value of it when t = 10, after 10 years.
There are 5 counts in half a second
Answer:
91
Step-by-step explanation:
85=last 4 tests
(85+x)/2=88
85+x=176
x=91
Answer:
MLEF
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Step-by-step explanation:
I hope this helps...
Answer:
a) M =82
Step-by-step explanation:
Let´s study this as a Normal distribution.
As we know in a normal distribution the z score is = (X-μ)/(sd/sqrt(n))
where
X = mean for the taken sample = What we want to know in this problem
μ = Total population mean =80
sd= standard deviation= 12
n = sample size=9
So in this case z=( X-80)/(12/sqr(9))= (X-80)/4
also we know that the effect size taken by the machine is 0.5, which is the same as the z-score
so...
0.5 = (X-80)/4 => 0.5*4 = X-80
2+80 = X
X = 82
