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3 years ago

Use long division to solve (x^3-2x^2-8) / (x+2)

Mathematics

1 answer:

sergeinik [125]3 years ago

3 0

Answer:

-8 is the answer

Step-by-step explanation:

that is the answer.

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ASAP!<br> lines p and q are parallel what is the sum of the degrees measure of angles x and y

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90? there’s a 45 degree angle at the bottom left and it looks like the same angle as x and y

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3 years ago

It takes Aaron 5 minutes to squeeze the juice from 3 grapefruits. At this rate, how many minutes will it take him to squeeze the

aliya0001 [1]

20 minutes because 12/3=4 and 4x5=20

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3 years ago

Malcom is filling bags with rice . He starts with a 5 1/4 pound container of rice and fills each bag with 5/8 pounds of rice . H

timama [110]

Answer:

Malcolm would fill 8 bags of rice.

Step-by-step explanation:

The size of the container of rice = 5 $\frac{1}{4}$ pounds = $\frac{21}{4}$ pounds.

Each bag of rice has a capacity of $\frac{5}{8}$ pounds.

The number of bags of rice that Malcolm fills = $\frac{total quantity of rice}{capacity of each bag}$

= $\frac{21}{4}$ ÷ $\frac{5}{8}$

= $\frac{21}{4}$ x $\frac{8}{5}$

= $\frac{42}{5}$

= 8 $\frac{2}{5}$

Therefore, Malcolm would be able to fill 8 bags of rice.

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4 years ago

Giving brainiest, thank you, and follow<br>find the missing side length, m.

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3 years ago

Read 2 more answers

After the mill in a small town closed down in 1970, the population of that town started decreasing according to the law of expon

wlad13 [49]

Answer:

$P_o = \frac{143000}{e^{-20*0.01303024661}}=110193.69$

And we can round this to the nearest up integer and we got 110194.

Step-by-step explanation:

The natural growth and decay model is given by:

$\frac{dP}{dt}=kP$ (1)

Where P represent the population and t the time in years since 1970.

If we integrate both sides from equation (1) we got:

$\int \frac{dP}{P} =\int kdt$

$ln|P| =kt +c$

And if we apply exponentials on both sides we got:

$P= e^{kt} e^k$

And we can assume $e^k = P_o$

And we have this model:

$P(t) = P_o e^{kt}$

And for this case we want to find $P_o$

By 1990 we have t=20 years since 1970 and we have this equation:

$143000 = P_o e^{20k}$

And we can solve for $P_o$ like this:

$P_o = \frac{143000}{e^{20k}}$ (1)

By 2019 we have 49 years since 1970 the equation is given by:

$98000 = P_o e^{49k}$ (2)

And replacing $P_o$ from equation (1) we got:

$98000=\frac{143000}{e^{20k}} e^{49k} =143000 e^{29k}$

We can divide both sides by 143000 we got:

$\frac{98000}{143000} =0.685 = e^{29k}$

And if we apply ln on both sides we got:

$ln(0.685) = 29k$

And then k =-0.01303024661[/tex]

And replacing into equation (1) we got:

$P_o = \frac{143000}{e^{-20*0.01303024661}}=110193.69$

And we can round this to the nearest up integer and we got 110194.

7 0

3 years ago