Metals tend to have a_______ attraction for electrons Answer plz

How do biotic factors impact ecological organization?

love history [14]

Answer:

plz mark as BRAINLIEST plz

Explanation:

The biotic factors in an ecosystem are the living organisms, such as animals. Biotic factors in an ecosystem are the participants in the food web, and they rely on each other for survival. ... These living organisms affect each other and influence the health of the ecosystem.

3 0

4 years ago

1.) Rust forms when Fe, O₂, and H₂O react in the balanced equation below;

valentinak56 [21]

Answer:

1.) A.) The limiting reactant is Fe.

B.) 16.17 g.

2.) 84.70 %.

Explanation:

For the balanced equation:

2Fe(s) + O₂(g) + 2H₂O(l) → 2Fe(OH)₂(s).

2.0 moles of Fe reacts with 1.0 mole of oxygen and 2.0 moles of water to produce 2.0 moles of Fe(OH)₂.

A.) Which of these reactants is the limiting reagent?

To determine the limiting reactant, we should calculate the no. of moles of reactants using the relation: n = mass/molar mass.

Suppose that water is exist in excess.

no. of moles Fe = mass/atomic mass = (10.0 g)/(55.845 g/mol) = 0.179 mol ≅ 0.18 mol.

no. of moles of O₂ = mass/molar mass = (4.0 g)/(32.0 g/mol) = 0.125 mol.

Since from the balanced equation; every 2.0 moles of Fe reacts with 1.0 mole of oxygen.

So, 0.18 mol of Fe reacts with 0.09 mol of O₂.

Thus, the limiting reactant is Fe.

The reactant in excess is O₂ (0.125 mol - 0.09 mol = 0.035 mol).

B.) How many grams of Fe(OH)₂ are formed?

Using cross multiplication:

∵ 2.0 moles of Fe produce → 2.0 moles of Fe(OH)₂.

∴ 0.18 moles of Fe produce → 0.18 moles of Fe(OH)₂.

∴ The mass (no. of grams) of produced 0.18 mol of Fe(OH)₂ = no. of moles x molar mass = (0.18 mol)(89.86 g/mol) = 16.17 g.

2.) (Using the reaction listed in question 1.) If 2.00 g Fe is reacted with an excess of O₂ and H₂0, and a total of 2.74 g of Fe(OH)₂ is actually obtained, what is the % yield?

The % yield = [(actual mass/calculated mass)] x 100.

The actual mass = 2.74 g.

We need to calculate the theoretical mass:

Firstly, we should calculate the no. of moles of reactants using the relation: n = mass/molar mass.

no. of moles Fe = mass/atomic mass = (2.0 g)/(55.845 g/mol) = 0.0358 mol ≅ 0.036 mol.

Using cross multiplication:

∵ 2.0 moles of Fe produce → 2.0 moles of Fe(OH)₂.

∴ 0.036 moles of Fe produce → 0.036 moles of Fe(OH)₂.

∴ The calculated mass (no. of grams) of produced 0.036 mol of Fe(OH)₂ = no. of moles x molar mass = (0.036 mol)(89.86 g/mol) = 3.235 g.

∴ The % yield = [(actual mass/calculated mass)] x 100 = [(2.74 g/3.235 g)] x 100 = 84.70 %.

4 0

4 years ago

Which of the following demonstrates a poor internal control procedure?

Alex_Xolod [135]

Answer: The bookkeeper makes cash deposits and records journal entries related to cash, while the treasurer prepares the bank reconciliation.

Explanation: The bookkeeper in an organization is the person in charge of records keeping, his basic task is to keep financial records and therefore the bookkeeper has no business handling physical cash in an organization.

The financial secretary on the hand is in charge saving cash income and withdrawal of cash from an organization, this is done with the organization's accountant approval.

5 0

3 years ago

Which equation represents a neutralization reaction? A. 4Fe(s) + 3O2(g) → 2Fe2O3(s) B. 2H2(g) + O2(g) → 2H2O() C. HNO3(aq) + KOH

devlian [24]

Answer : The correct option is, (C)

Explanation :

A. $4Fe(s)+3O_2(g)\rightarrow 2Fe_2O_3(s)$

This is synthesis reaction in which the two or more reactant react to give a single product.

B. $2H_2(g)+O_2(g)\rightarrow 2H_2O(l)$

This is combination reaction in which the two reactants combine to form a single product.

C. $HNO_3(aq)+KOH(aq)\rightarrow KNO_3(aq)+H_2O(l)$

This is a neutralization reaction in which an acid react with a base to give a salt and water as a product.

D. $AgNO_3(aq)+KCl(aq)\rightarrow KNO_3(aq)+AgCl(s)$

This is a double displacement reaction in which the positive cation and negative anion of two reactants exchange their places to give two new products.

Hence, the reaction (C) is a neutralization reaction.

4 0

3 years ago

Read 2 more answers

There are eight consitutional isomers with the molecular formula C4H11N.

Dmitriy789 [7]

Answer:

See figure 1

Explanation:

We have to remember that in the isomer structures we have to change the structure but we have to maintain the same formula, in this case $C_4H_1_1N$ .

In the formula, we have 1 nitrogen atom. Therefore we will have as a main functional group the amine group.

In the amines, we have different types of amines. Depending on the number of carbons bonded to the "N" atom. In the primary amines, we have only 1 C-H. In the secondary amines, we have two C-N bonds and in the tertiary amines, we have three C-N bonds.

With this in mind, we can have:

-) Primary amines:

1) n-butyl amine

2) sec-butyl amine including 2 optical isomers

3) isobutyl amine

4) tert-butyl amine

-) Secondary amines:

5) N-methyl n-propyl amine

6) N-methyl isopropyl amine

7) N, N-diethyl amine

-) Tertiary amines:

8) N-ethyl N, N-dimethyl amine

See figure 1

I hope it helps!

8 0

3 years ago