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Alinara [238K]
3 years ago
9

Type the max number of electrons that can be present in each shell or sub below

Chemistry
2 answers:
zhuklara [117]3 years ago
7 0

32 in n=5

4 in n= 2

2 in l=0

10 in 3d

2 in 2s

14 in 5f

Hatshy [7]3 years ago
7 0

Answer:

32 in n=5 shell

4 in n= 2 shell

2 in l=0 shell

10 in 3d shell

2 in 2s shell

14 in 5f shell

Explanation:

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How many grams of oxygen are required to react with 2.7 g of dihydrogen sulfide
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Answer:

Mass = 3.84 g

Explanation:

Given data:

Mass of hydrogen sulfide = 2.7 g

Mass of oxygen required = ?

Solution:

Chemical equation:

2H₂S + 3O₂ →  2H₂O + 2SO₂

Number of moles of hydrogen sulfide:

Number of moles = mass/ molar mass

Number of moles = 2.7 g / 34 g/mol

Number of moles = 0.08 mol

Now we will compare the moles of hydrogen sulfide with oxygen.

                               H₂S           :             O₂

                                  2             :             3

                                  0.08       :            3/2 ×0.08 = 0.12 mol

Mass of oxygen;

Mass = number of moles × molar mass

Mass = 0.12 mol × 32 g/mol

Mass = 3.84 g

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