Answer:
Check the explanation
Step-by-step explanation:
1) Algorithm for finding the new optimal flux: 1. Let E' be the edges eh E for which f(e)>O, and let G = (V,E). Find in Gi a path Pi from s to u and a path 
, from v to t.
2) [Special case: If , and 
have some edge e in common, then Piu[(u,v)}uPx has a directed cycle containing (u,v). In this instance, the flow along this cycle can be reduced by a single unit without any need to change the size of the overall flow. Return the resulting flow.]
3) Reduce flow by one unit along 
4) Run Ford-Fulkerson with this sterling flow.
Justification and running time: Say the original flow has see F. Lees ignore the special case (4 After step (3) Of the elgorithuk we have a legal flaw that satisfies the new capacity constraint and has see F-1. Step (4). FOrd-Fueerson, then gives us the optimal flow under the new cePacie co mint. However. we know this flow is at most F, end thus Ford-Fulkerson runs for just one iteration. Since each of the steps is linear, the total running time is linear, that is, O(lVl + lEl).
A=p (1+rt)
A future value ?
p Principle 900
R interest rate 0.06
T time 9/12
A=900×(1+0.06×(9÷12))
A=940.5
The answer is 1
Work
11/6=1.833
You can serve 1.833 people? No because unfortunately, you can't feed a fraction of a person. So, you can actually only feed 1 person.
Answer:
14k
Step-by-step explanation:
add 10 and 4 because they both have k
Answer:
320 cm²
Step-by-step explanation:
If 3 units = 12cm
Then 1 unit = 12/3 = 4cm
Formula for Area Trapezoid = height*(base1+base2)/2
Base 1 = 12
Base 2 = 7 * 4 = 28
12 + 28 = 40
40 * (4*4) = 40 * 16 = 640
640 / 2 = 320
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-Chetan K
