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3 years ago

Please help me with his problem

Mathematics

1 answer:

zubka84 [21]3 years ago

7 0

Answer:

g. m∠1 = m∠3

Step-by-step explanation:

F would be false because m∠1 does NOT equal m∠2, if it did the wood would be perpendicular.

H is true, but not the correct answer. None of the angles given are on the other piece of parallel wood, giving nothing to compare.

J would be false because m∠3 does NOT equal m∠4, if it did the wood would be perpendicular.

G is correct, because it is a true statement that gives an angle on each piece of wood.

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I NEED HELP PLEASE!!!

solmaris [256]

Answer:

Step-by-step explanation:

cos(theta) is positive in IV quadrant and sin(theta)=sqrt(13^2-5^2)/13=-12/13

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2 years ago

What time does the clock show? 12 1 11 10 3 - 8 4. 1 7 6 5

amm1812

Answer:

6:59

Step-by-step explanation:

Hour : Minute

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3 years ago

Read 2 more answers

-x^(2)-12=-87 Please explain your answer, and how I make the x positive

spayn [35]

Solve for x over the real numbers:
-x^2 - 12 = -87
Add 12 to both sides:
-x^2 = -75
Multiply both sides by -1:
x^2 = 75
Take the square root of both sides:
Answer: x = 5 sqrt(3) or x = -5 sqrt(3) both Answers are correct

7 0

3 years ago

If we add 9 tens 5 hundreds and 3 ones then the result is?

ioda

Answer:

9 tens = 90

5 hundreds = 500

3 ones = 3

on adding them we get, 500 + 90 + 3 = 593

6 0

1 year ago

Read 2 more answers

Can you please help me out

Taya2010 [7]

The bag contains,

Red (R) marbles is 9, Green (G) marbles is 7 and Blue (B) marbles is 4,

Total marbles (possible outcome) is,

$\text{Total marbles = (R) + (G) +(B) = 9 + 7 + 4 = 20 marbles}$

Let P(R) represent the probablity of picking a red marble,

P(G) represent the probability of picking a green marble and,

P(B) represent the probability of picking a blue marble.

Probability , P, is,

$\text{Prob, P =}\frac{required\text{ outcome}}{possible\text{ outcome}}$ $\begin{gathered} P(R)=\frac{9}{20} \\ P(G)=\frac{7}{20} \\ P(B)=\frac{4}{20} \end{gathered}$

Probablity of drawing a Red marble (R) and then a blue marble (B) without being replaced,

That means once a marble is drawn, the total marbles (possible outcome) reduces as well,

$\begin{gathered} \text{Prob of a red marble P(R) =}\frac{9}{20} \\ \text{Prob of }a\text{ blue marble =}\frac{4}{19} \\ \text{After a marble is selected without replacement, marbles left is 19} \\ \text{Prob of red marble + prob of blue marble = P(R) + P(B) = }\frac{9}{20}+\frac{4}{19}=\frac{251}{380} \\ \text{Hence, the probability is }\frac{251}{380} \end{gathered}$

Hence, the best option is G.

5 0

1 year ago