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Cloud [144]
3 years ago
5

A car has a mass of 1,200 kg. what is it's acceleration when the engine exerts a force of 600 N ? (formula: F= ma)

Mathematics
2 answers:
tia_tia [17]3 years ago
6 0

Answer:

In this case, the mass of the car and the force exerted on it are provided as information. Therefore, the acceleration of the car is 0.5 m s−2 when its engine exerts a force of 600 N

Step-by-step explanation:

docker41 [41]3 years ago
6 0
F=600N
M=1,200kg

600N=(1,200kg)(acceleration)

Acceleration=0.5 m/s^2
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Answer:

The ball shall keep rising tills its velocity becomes zero. Let it rise to a height h feet from point of projection.

Step-by-step explanation:

Let us take the point of projection of the ball as origin of the coordinate system, the upward direction as positive and down direction as negative.

Initial velocity u with which the ball is projected upwards = + 120 ft/s

Uniform acceleration a acting on the ball is to acceleration due to gravity = - 32 ft/s²

The ball shall keep rising tills its velocity becomes zero. Let it rise to a height h feet from point of projection.

Using the formula:

v² - u² = 2 a h,

where

u = initial velocity of the ball = +120 ft/s

v = final velocity of the ball at the highest point = 0 ft/s

a = uniform acceleration acting on the ball = -32 ft/s²

h = height attained

Substituting the values we get;

0² - 120² = 2 × (- 32) h

=> h = 120²/2 × 32 = 225 feet

The height of the ball from the ground at its highest point = 225 feet + 12 feet = 237 feet.

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Answer:

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Step-by-step explanation:

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